Q.63. Given below are two statements: Statement I: Crystal Field Stabilization Energy (CFSE) of [Cr(

Q: What is the correct answer for JEE Main Chemistry Q63?

The correct answer is A. Statement I: CFSE of [Cr(H$_2$O)$_6$]$^{2+}$ is greater than that of [Mn(H$_2$O)$_6$]$^{2+}$. Cr is in +2 oxidation state, so it is a $d^4$ ion. Mn is in +2 oxidation state, so it is a $d^5$ ion. H$_2$O is a weak field ligand. For a $d^4$ ion in an octahedral weak field, the configuration is $t_{2g}^3 e_g^1$. CFSE $= (-0.4 \times 3 + 0.6 \times 1)\Delta_o = -0.6\Delta_o$. For a $d^5$ ion in an oct

Q: Q.63. Given below are two statements: Statement I: Crystal Field Stabilization Energy (CFSE) of [Cr(HO)] is greater than that of [Mn(HO)]. Statement II: Potassium ferricyanide has a greater spin-only…

The correct answer is A. Statement I: CFSE of [Cr(H$_2$O)$_6$]$^{2+}$ is greater than that of [Mn(H$_2$O)$_6$]$^{2+}$. Cr is in +2 oxidation state, so it is a $d^4$ ion. Mn is in +2 oxidation state, so it is a $d^5$ ion. H$_2$O is a weak field ligand. For a $d^4$ ion in an octahedral weak field, the configuration is $t_{2g}^3 e_g^1$. CFSE $= (-0.4 \times 3 + 0.6 \times 1)\Delta_o = -0.6\Delta_o$. For a $d^5$ ion in an oct

Q: What are the options for this JEE Main Chemistry question?

A. Both Statement I and Statement II are true · B. Both Statement I and Statement II are false · C. Statement I is true but Statement II is false · D. Statement I is false but Statement II is true

Question

Q.63. Given below are two statements: Statement I: Crystal Field Stabilization Energy (CFSE) of [Cr(HO)] is greater than that of [Mn(HO)]. Statement II: Potassium ferricyanide has a greater spin-only magnetic moment than sodium Ferrocyanide. In the light of the above statements, choose the correct answer from the options given below:

FirstInTest · Accepted Answer

Statement I: CFSE of [Cr(H$_2$O)$_6$]$^{2+}$ is greater than that of [Mn(H$_2$O)$_6$]$^{2+}$. Cr is in +2 oxidation state, so it is a $d^4$ ion. Mn is in +2 oxidation state, so it is a $d^5$ ion. H$_2$O is a weak field ligand. For a $d^4$ ion in an octahedral weak field, the configuration is $t_{2g}^3 e_g^1$. CFSE $= (-0.4 	imes 3 + 0.6 	imes 1)\Delta_o = -0.6\Delta_o$. For a $d^5$ ion in an octahedral weak field, the configuration is $t_{2g}^3 e_g^2$. CFSE $= (-0.4 	imes 3 + 0.6 	imes 2)\Delta_o = 0$. Since $-0.6\Delta_o$ is a negative value and $0$ is zero, the magnitude of CFSE for [Cr(H$_2$O)$_6$]$^{2+}$ (0.6$\Delta_o$) is greater than that for [Mn(H$_2$O)$_6$]$^{2+}$ (0). So, Statement I is true. Statement II: Potassium ferricyanide has a greater spin-only magnetic moment than sodium Ferrocyanide. Potassium ferricyanide is K$_3$[Fe(CN)$_6$]. Iron is in +3 oxidation state, so it is a $d^5$ ion. CN$^-$ is a strong field ligand. For a $d^5$ ion in an octahedral strong field, the configuration is $t_{2g}^5 e_g^0$. Number of unpaired electrons $n=1$. Spin-only magnetic moment $\mu = \sqrt{n(n+2)} = \sqrt{1(1+2)} = \sqrt{3}$ BM. Sodium ferrocyanide is Na$_4$[Fe(CN)$_6$]. Iron is in +2 oxidation state, so it is a $d^6$ ion. CN$^-$ is a strong field ligand. For a $d^6$ ion in an octahedral strong field, the configuration is $t_{2g}^6 e_g^0$. Number of unpaired electrons $n=0$. Spin-only magnetic moment $\mu = \sqrt{0(0+2)} = 0$ BM. Since $\sqrt{3}$ BM > 0 BM, potassium ferricyanide has a greater spin-only magnetic moment than sodium ferrocyanide. So, Statement II is true. Both statements are true.

Answer

Both Statement I and Statement II are true

Answer

Both Statement I and Statement II are false

Answer

Statement I is true but Statement II is false

Answer

Statement I is false but Statement II is true

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