Q.52. The species having identical radii according to the Bohr's theory are : A. H (first orbit) B.

Q: What is the correct answer for JEE Main Chemistry Q52?

The correct answer is B. Sol. According to Bohr's theory, radius $r_n = \frac{n^2 a_0}{Z}$. For identical radii, $\frac{n^2}{Z}$ must be same. A. H (first orbit): $n=1, Z=1 \Rightarrow \frac{1^2}{1} = 1$ B. He$^+$ (first orbit): $n=1, Z=2 \Rightarrow \frac{1^2}{2} = 0.5$ C. He$^+$ (second orbit): $n=2, Z=2 \Rightarrow \frac{2^2}{2} = 2$ D. Li$^{2+}$ (first orbit): $n=1, Z=3 \Rightarrow \frac{1^2}{3} = 0.33$ E. Be$^{3+}$ (

Q: Q.52. The species having identical radii according to the Bohr's theory are : A. H (first orbit) B. He (first orbit) C. He (second orbit) D. Li (first orbit) E. Be (Second orbit) Choose the correct…

The correct answer is B. Sol. According to Bohr's theory, radius $r_n = \frac{n^2 a_0}{Z}$. For identical radii, $\frac{n^2}{Z}$ must be same. A. H (first orbit): $n=1, Z=1 \Rightarrow \frac{1^2}{1} = 1$ B. He$^+$ (first orbit): $n=1, Z=2 \Rightarrow \frac{1^2}{2} = 0.5$ C. He$^+$ (second orbit): $n=2, Z=2 \Rightarrow \frac{2^2}{2} = 2$ D. Li$^{2+}$ (first orbit): $n=1, Z=3 \Rightarrow \frac{1^2}{3} = 0.33$ E. Be$^{3+}$ (

Q: What are the options for this JEE Main Chemistry question?

A. A and C Only · B. A and E Only · C. B and E Only · D. C and D Only

Question

Q.52. The species having identical radii according to the Bohr's theory are : A. H (first orbit) B. He (first orbit) C. He (second orbit) D. Li (first orbit) E. Be (Second orbit) Choose the correct answer from the options given below:

FirstInTest · Accepted Answer

Sol. According to Bohr's theory, radius $r_n = \frac{n^2 a_0}{Z}$. For identical radii, $\frac{n^2}{Z}$ must be same. A. H (first orbit): $n=1, Z=1 \Rightarrow \frac{1^2}{1} = 1$ B. He$^+$ (first orbit): $n=1, Z=2 \Rightarrow \frac{1^2}{2} = 0.5$ C. He$^+$ (second orbit): $n=2, Z=2 \Rightarrow \frac{2^2}{2} = 2$ D. Li$^{2+}$ (first orbit): $n=1, Z=3 \Rightarrow \frac{1^2}{3} = 0.33$ E. Be$^{3+}$ (Second orbit): $n=2, Z=4 \Rightarrow \frac{2^2}{4} = 1$ Comparing the values: A and E have $\frac{n^2}{Z}=1$. So H (first orbit) and Be$^{3+}$ (second orbit) have identical radii.

Answer

A and C Only

Answer

A and E Only

Answer

B and E Only

Answer

C and D Only

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