Q.60. Consider the metal complexes [Ni(en)] (A), [NiCl] (B) and [Ni(NH)] (C). Choose the CORRECT opt

Q: What is the correct answer for JEE Main Chemistry Q60?

The correct answer is B. Sol. For all complexes, Ni is in +2 oxidation state, so Ni$^{2+}$ has $d^8$ configuration. (A) [Ni(en)$_3$]$^{2+}$: 'en' (ethylenediamine) is a strong field ligand. It's an octahedral complex. For $d^8$ in strong field, electrons pair up. Configuration: $t_{2g}^6 e_g^2$. Number of unpaired electrons = 2. (B) [NiCl$_4$]$^{2-}$: Cl$^-$ is a weak field ligand. It's a tetrahedral complex. For $d^8$ in

Q: Q.60. Consider the metal complexes [Ni(en)] (A), [NiCl] (B) and [Ni(NH)] (C). Choose the CORRECT option by considering the number of unpaired electron present in (A), (B) and (C) respectively and the…

The correct answer is B. Sol. For all complexes, Ni is in +2 oxidation state, so Ni$^{2+}$ has $d^8$ configuration. (A) [Ni(en)$_3$]$^{2+}$: 'en' (ethylenediamine) is a strong field ligand. It's an octahedral complex. For $d^8$ in strong field, electrons pair up. Configuration: $t_{2g}^6 e_g^2$. Number of unpaired electrons = 2. (B) [NiCl$_4$]$^{2-}$: Cl$^-$ is a weak field ligand. It's a tetrahedral complex. For $d^8$ in

Q: What are the options for this JEE Main Chemistry question?

A. 2, 2, 2 and (A) > (C) > (B) · B. 0, 2, 0 and (A) > (C) > (B) · C. 2, 2, 0 and (B) > (C) > (A) · D. 2, 2, 2 and (C) > (A) > (B)

Question

Q.60. Consider the metal complexes [Ni(en)] (A), [NiCl] (B) and [Ni(NH)] (C). Choose the CORRECT option by considering the number of unpaired electron present in (A), (B) and (C) respectively and the order of frequency of absorption.

FirstInTest · Accepted Answer

Sol. For all complexes, Ni is in +2 oxidation state, so Ni$^{2+}$ has $d^8$ configuration. (A) [Ni(en)$_3$]$^{2+}$: 'en' (ethylenediamine) is a strong field ligand. It's an octahedral complex. For $d^8$ in strong field, electrons pair up. Configuration: $t_{2g}^6 e_g^2$. Number of unpaired electrons = 2. (B) [NiCl$_4$]$^{2-}$: Cl$^-$ is a weak field ligand. It's a tetrahedral complex. For $d^8$ in tetrahedral field, configuration: $e^4 t_2^4$. Number of unpaired electrons = 2. (C) [Ni(NH$_3$)$_6$]$^{2+}$: NH$_3$ is a strong field ligand. It's an octahedral complex. For $d^8$ in strong field, electrons pair up. Configuration: $t_{2g}^6 e_g^2$. Number of unpaired electrons = 2. So, the number of unpaired electrons for (A), (B), (C) are 2, 2, 2 respectively. Order of frequency of absorption depends on the ligand field strength. Stronger the ligand, higher the crystal field splitting energy ($\Delta_o$), and thus higher the frequency of light absorbed. Ligand field strength order: en > NH$_3$ > Cl$^-$ Therefore, the order of frequency of absorption is (A) > (C) > (B).

Answer

2, 2, 2 and (A) > (C) > (B)

Answer

0, 2, 0 and (A) > (C) > (B)

Answer

2, 2, 0 and (B) > (C) > (A)

Answer

2, 2, 2 and (C) > (A) > (B)

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