Q.59. Given below are two statements : Statement-I : Aluminium is more electropositive than thallium

Q: What is the correct answer for JEE Main Chemistry Q59?

The correct answer is A. Statement-I: The standard electrode potential for Al ($E^0_{\mathrm{Al^{3+}/Al}}$ = -1.66 V) is negative, indicating it is easily oxidized and thus more electropositive. The standard electrode potential for Tl ($E^0_{\mathrm{Tl^{3+}/Tl}}$ = +1.26 V) is positive, indicating it is less easily oxidized and thus less electropositive. Therefore, Aluminium is more electropositive than thallium. Statemen

Q: Q.59. Given below are two statements : Statement-I : Aluminium is more electropositive than thallium as the standard electrode potential value of is negative and is positive. Statement-II: The sum…

The correct answer is A. Statement-I: The standard electrode potential for Al ($E^0_{\mathrm{Al^{3+}/Al}}$ = -1.66 V) is negative, indicating it is easily oxidized and thus more electropositive. The standard electrode potential for Tl ($E^0_{\mathrm{Tl^{3+}/Tl}}$ = +1.26 V) is positive, indicating it is less easily oxidized and thus less electropositive. Therefore, Aluminium is more electropositive than thallium. Statemen

Q: What are the options for this JEE Main Chemistry question?

A. Both Statement-I and Statement-II are true. · B. Both Statement-I and Statement-II are false. · C. Statement-I is true but Statement-II is false. · D. Statement-I is false but Statement-II is true.

Question

Q.59. Given below are two statements : Statement-I : Aluminium is more electropositive than thallium as the standard electrode potential value of  is negative and  is positive. Statement-II: The sum of first three ionization enthalpies of boron is very high when compared to that of aluminium. Due to this reason boron forms covalent compounds only and aluminium forms Al ion. In the light of the above statements, choose the correct answer from the options given below.

FirstInTest · Accepted Answer

Statement-I: The standard electrode potential for Al ($E^0_{\mathrm{Al^{3+}/Al}}$ = -1.66 V) is negative, indicating it is easily oxidized and thus more electropositive. The standard electrode potential for Tl ($E^0_{\mathrm{Tl^{3+}/Tl}}$ = +1.26 V) is positive, indicating it is less easily oxidized and thus less electropositive. Therefore, Aluminium is more electropositive than thallium. Statement-I is true.
Statement-II: Boron has a very small size and high nuclear charge, leading to very high ionization enthalpies. The sum of the first three ionization enthalpies of boron (801 + 2427 + 3659 = 6887 kJ/mol) is indeed very high. This high energy requirement for ionization makes it difficult for boron to form B$^{3+}$ ions, so it primarily forms covalent compounds. Aluminium, being larger, has lower ionization enthalpies and readily forms Al$^{3+}$ ions. Therefore, Statement-II is true.
Both statements are true, and Statement-II provides a correct explanation for the chemical behavior (covalent vs. ionic) related to ionization enthalpies.

Answer

Both Statement-I and Statement-II are true.

Answer

Both Statement-I and Statement-II are false.

Answer

Statement-I is true but Statement-II is false.

Answer

Statement-I is false but Statement-II is true.

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