In the Sandmeyer's reaction, a primary aromatic amine is converted to a diazonium salt, which then r

Q: What is the correct answer for CBSE12?

The correct answer is B. The Sandmeyer's reaction involves treating a freshly prepared diazonium salt with cuprous chloride (Cu₂Cl₂) or cuprous bromide (Cu₂Br₂) to replace the diazonium group with -Cl or -Br, respectively. KI is used for aryl iodides, FeX₃ is a Lewis acid catalyst for direct halogenation, and NaNO₂ is used in the first step (diazotization) with HX.

Q: In the Sandmeyer's reaction, a primary aromatic amine is converted to a diazonium salt, which then reacts with which reagent to form an aryl chloride or bromide?

The correct answer is B. The Sandmeyer's reaction involves treating a freshly prepared diazonium salt with cuprous chloride (Cu₂Cl₂) or cuprous bromide (Cu₂Br₂) to replace the diazonium group with -Cl or -Br, respectively. KI is used for aryl iodides, FeX₃ is a Lewis acid catalyst for direct halogenation, and NaNO₂ is used in the first step (diazotization) with HX.

Q: What are the options for this CBSE12 question?

A. KI · B. Cu₂X₂ (where X = Cl or Br) · C. FeX₃ · D. NaNO₂

Question

In the Sandmeyer's reaction, a primary aromatic amine is converted to a diazonium salt, which then reacts with which reagent to form an aryl chloride or bromide?

FirstInTest · Accepted Answer

The Sandmeyer's reaction involves treating a freshly prepared diazonium salt with cuprous chloride (Cu₂Cl₂) or cuprous bromide (Cu₂Br₂) to replace the diazonium group with -Cl or -Br, respectively. KI is used for aryl iodides, FeX₃ is a Lewis acid catalyst for direct halogenation, and NaNO₂ is used in the first step (diazotization) with HX.

Answer

KI

Answer

Cu₂X₂ (where X = Cl or Br)

Answer

FeX₃

Answer

NaNO₂

Related Questions

More from CBSE12

Practice Other NCERT Exams

Practice More CBSE12 Questions