Arrange the following alkyl halides in decreasing order of their boiling points: CH₃I, CH₃Br, CH₃Cl,

Q: What is the correct answer for CBSE12?

The correct answer is A. For the same alkyl group, the boiling points of alkyl halides decrease in the order RI > RBr > RCl > RF. This is because, with an increase in the size and mass of the halogen atom (I > Br > Cl > F), the magnitude of van der Waals forces of attraction increases, leading to higher boiling points.

Q: Arrange the following alkyl halides in decreasing order of their boiling points: CH₃I, CH₃Br, CH₃Cl, CH₃F.

The correct answer is A. For the same alkyl group, the boiling points of alkyl halides decrease in the order RI > RBr > RCl > RF. This is because, with an increase in the size and mass of the halogen atom (I > Br > Cl > F), the magnitude of van der Waals forces of attraction increases, leading to higher boiling points.

Q: What are the options for this CBSE12 question?

A. CH₃I > CH₃Br > CH₃Cl > CH₃F · B. CH₃F > CH₃Cl > CH₃Br > CH₃I · C. CH₃Cl > CH₃Br > CH₃I > CH₃F · D. CH₃Br > CH₃I > CH₃Cl > CH₃F

Question

Arrange the following alkyl halides in decreasing order of their boiling points: CH₃I, CH₃Br, CH₃Cl, CH₃F.

FirstInTest · Accepted Answer

For the same alkyl group, the boiling points of alkyl halides decrease in the order RI > RBr > RCl > RF. This is because, with an increase in the size and mass of the halogen atom (I > Br > Cl > F), the magnitude of van der Waals forces of attraction increases, leading to higher boiling points.

Answer

CH₃I > CH₃Br > CH₃Cl > CH₃F

Answer

CH₃F > CH₃Cl > CH₃Br > CH₃I

Answer

CH₃Cl > CH₃Br > CH₃I > CH₃F

Answer

CH₃Br > CH₃I > CH₃Cl > CH₃F

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