If the position of an electron is measured with an accuracy of 0.002 nm, calculate the uncertainty i

Q: What is the correct answer for CBSE11?

The correct answer is C. The Heisenberg Uncertainty Principle is ΔxΔp ≥ h/4π. We are given Δx = 0.002 nm = 0.002 x 10⁻⁹ m = 2 x 10⁻¹² m. So, Δp ≥ h / (4πΔx) = (6.626 x 10⁻³⁴ J s) / (4 x 3.1416 x 2 x 10⁻¹² m) = (6.626 x 10⁻³⁴) / (2.51328 x 10⁻¹¹) kg m s⁻¹ = 2.635 x 10⁻²³ kg m s⁻¹. The question asks for the uncertainty in momentum, which is Δp. The closest option is 2.64 x 10⁻²³ kg m s⁻¹. However, the provided solution in t

Q: If the position of an electron is measured with an accuracy of 0.002 nm, calculate the uncertainty in its momentum. (h = 6.626 x 10⁻³⁴ J s)

The correct answer is C. The Heisenberg Uncertainty Principle is ΔxΔp ≥ h/4π. We are given Δx = 0.002 nm = 0.002 x 10⁻⁹ m = 2 x 10⁻¹² m. So, Δp ≥ h / (4πΔx) = (6.626 x 10⁻³⁴ J s) / (4 x 3.1416 x 2 x 10⁻¹² m) = (6.626 x 10⁻³⁴) / (2.51328 x 10⁻¹¹) kg m s⁻¹ = 2.635 x 10⁻²³ kg m s⁻¹. The question asks for the uncertainty in momentum, which is Δp. The closest option is 2.64 x 10⁻²³ kg m s⁻¹. However, the provided solution in t

Q: What are the options for this CBSE11 question?

A. 2.64 x 10⁻²³ kg m s⁻¹ · B. 2.64 x 10⁻²⁵ kg m s⁻¹ · C. 2.64 x 10⁻²⁶ kg m s⁻¹ · D. 2.64 x 10⁻²⁷ kg m s⁻¹

Question

If the position of an electron is measured with an accuracy of 0.002 nm, calculate the uncertainty in its momentum. (h = 6.626 x 10⁻³⁴ J s)

FirstInTest · Accepted Answer

The Heisenberg Uncertainty Principle is ΔxΔp ≥ h/4π. We are given Δx = 0.002 nm = 0.002 x 10⁻⁹ m = 2 x 10⁻¹² m. So, Δp ≥ h / (4πΔx) = (6.626 x 10⁻³⁴ J s) / (4 x 3.1416 x 2 x 10⁻¹² m) = (6.626 x 10⁻³⁴) / (2.51328 x 10⁻¹¹) kg m s⁻¹ = 2.635 x 10⁻²³ kg m s⁻¹. The question asks for the uncertainty in momentum, which is Δp. The closest option is 2.64 x 10⁻²³ kg m s⁻¹. However, the provided solution in the textbook for a similar problem (2.61) gives a value of 2.64 x 10⁻²³ kg m s⁻¹ for Δp. Let's recheck the calculation: Δp = 6.626E-34 / (4 * 3.1416 * 2E-12) = 2.635E-23. The options provided are quite different. Let's assume the question meant Δx = 0.002 nm, and the options are based on that. The calculation yields 2.64 x 10⁻²³ kg m s⁻¹.

Answer

2.64 x 10⁻²³ kg m s⁻¹

Answer

2.64 x 10⁻²⁵ kg m s⁻¹

Answer

2.64 x 10⁻²⁶ kg m s⁻¹

Answer

2.64 x 10⁻²⁷ kg m s⁻¹

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