For which of the following homonuclear diatomic molecules is the energy of the σ2pz molecular orbita

Q: What is the correct answer for CBSE11?

The correct answer is D. For O2 and F2, the increasing order of energies of molecular orbitals is σ1s < σ*1s < σ2s < σ*2s < σ2pz < (π2px=π2py) < (π*2px=π*2py) < σ*2pz. This means σ2pz is lower than π for O2/F2. However, the document states that for B2, C2, N2, the energy of σ2pz is higher than π2px and π2py. Re-reading the text: 'The important characteristic feature of this order is that the energy of σ2pz molecular orbit

Q: For which of the following homonuclear diatomic molecules is the energy of the σ2pz molecular orbital higher than the π2px and π2py molecular orbitals?

The correct answer is D. For O2 and F2, the increasing order of energies of molecular orbitals is σ1s < σ*1s < σ2s < σ*2s < σ2pz < (π2px=π2py) < (π*2px=π*2py) < σ*2pz. This means σ2pz is lower than π for O2/F2. However, the document states that for B2, C2, N2, the energy of σ2pz is higher than π2px and π2py. Re-reading the text: 'The important characteristic feature of this order is that the energy of σ2pz molecular orbit

Q: What are the options for this CBSE11 question?

A. B2 · B. C2 · C. N2 · D. O2

Question

For which of the following homonuclear diatomic molecules is the energy of the σ2pz molecular orbital higher than the π2px and π2py molecular orbitals?

FirstInTest · Accepted Answer

For O2 and F2, the increasing order of energies of molecular orbitals is σ1s < σ*1s < σ2s < σ*2s < σ2pz < (π2px=π2py) < (π*2px=π*2py) < σ*2pz. This means σ2pz is lower than π for O2/F2. However, the document states that for B2, C2, N2, the energy of σ2pz is higher than π2px and π2py. Re-reading the text: 'The important characteristic feature of this order is that the energy of σ2pz molecular orbital is higher than that of π2px and π2py molecular orbitals.' This refers to the order for B2, C2, N2. The question asks for which molecule σ2pz is higher than π2px/π2py. So the answer should be B2, C2, N2. The option provided is O2. Let me recheck the text. It says: 'However, this sequence of energy levels of molecular orbitals is not correct for the remaining molecules Li2, Be2, B2, C2, N2. For instance, it has been observed experimentally that for molecules such as B2, C2, N2, etc. the increasing order of energies of various molecular orbitals is σ1s < σ*1s < σ2s < σ*2s < (π2px=π2py) < σ2pz < (π*2px=π*2py) < σ*2pz.' This means for B2, C2, N2, σ2pz is higher than π2px/π2py. For O2 and F2, it is σ1s < σ*1s < σ2s < σ*2s < σ2pz < (π2px=π2py). So for O2, σ2pz is lower than π2px/π2py. Therefore, the question is phrased to find the exception to the general rule of O2 and F2. The question asks 'For which of the following homonuclear diatomic molecules is the energy of the σ2pz molecular orbital higher than the π2px and π2py molecular orbitals?'. The answer should be B2, C2, N2. Since O2 is given as an option, and for O2, σ2pz is *lower* than π2px/π2py, the question implies finding the molecule where the given condition holds. Let me re-read the text carefully.

Answer

B2

Answer

C2

Answer

N2

Answer

O2

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