An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neu

Q: What is the correct answer for CBSE11?

The correct answer is A. Let 'p' be the number of protons, 'n' be the number of neutrons, and 'e' be the number of electrons. Mass number A = p + n = 37. The ion has a -1 charge, so e = p + 1. Neutrons are 11.1% more than electrons, so n = e + 0.111e = 1.111e. Substitute e = p + 1 into the neutron equation: n = 1.111(p + 1). Now substitute n into the mass number equation: p + 1.111(p + 1) = 37. 2.111p + 1.111 = 37. 2.111p

Q: An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

The correct answer is A. Let 'p' be the number of protons, 'n' be the number of neutrons, and 'e' be the number of electrons. Mass number A = p + n = 37. The ion has a -1 charge, so e = p + 1. Neutrons are 11.1% more than electrons, so n = e + 0.111e = 1.111e. Substitute e = p + 1 into the neutron equation: n = 1.111(p + 1). Now substitute n into the mass number equation: p + 1.111(p + 1) = 37. 2.111p + 1.111 = 37. 2.111p

Q: What are the options for this CBSE11 question?

A. ³⁷Cl⁻ · B. ³⁷K⁻ · C. ³⁷F⁻ · D. ³⁷S⁻

Question

An ion with mass number 37 possesses one unit of negative charge. If the ion contains 11.1% more neutrons than the electrons, find the symbol of the ion.

FirstInTest · Accepted Answer

Let 'p' be the number of protons, 'n' be the number of neutrons, and 'e' be the number of electrons. Mass number A = p + n = 37. The ion has a -1 charge, so e = p + 1. Neutrons are 11.1% more than electrons, so n = e + 0.111e = 1.111e. Substitute e = p + 1 into the neutron equation: n = 1.111(p + 1). Now substitute n into the mass number equation: p + 1.111(p + 1) = 37. 2.111p + 1.111 = 37. 2.111p = 35.889. p = 17. The element with 17 protons is Chlorine (Cl). Since e = p + 1 = 17 + 1 = 18, and n = 1.111 * 18 = 20. So, A = 17 + 20 = 37. The ion is ³⁷Cl⁻.

Answer

³⁷Cl⁻

Answer

³⁷K⁻

Answer

³⁷F⁻

Answer

³⁷S⁻

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