Q.37. The electric potential as a function of x, y is given by . The electric field at a point (2, 3

Q: What is the correct answer for this exam Physics Q37?

The correct answer is A. The electric field $\vec{E}$ is related to the electric potential $V$ by $\vec{E} = -\nabla V = -(\frac{\partial V}{\partial x} \hat{i} + \frac{\partial V}{\partial y} \hat{j})$. Given $V = 5(x^2 - y^2)$. $\frac{\partial V}{\partial x} = 5(2x) = 10x$. $\frac{\partial V}{\partial y} = 5(-2y) = -10y$. So, $\vec{E} = -(10x \hat{i} - 10y \hat{j}) = -10x \hat{i} + 10y \hat{j}$. At point (2, 3) m, $x=2$

Q: Q.37. The electric potential as a function of x, y is given by . The electric field at a point (2, 3) m is _______ V/m.

The correct answer is A. The electric field $\vec{E}$ is related to the electric potential $V$ by $\vec{E} = -\nabla V = -(\frac{\partial V}{\partial x} \hat{i} + \frac{\partial V}{\partial y} \hat{j})$. Given $V = 5(x^2 - y^2)$. $\frac{\partial V}{\partial x} = 5(2x) = 10x$. $\frac{\partial V}{\partial y} = 5(-2y) = -10y$. So, $\vec{E} = -(10x \hat{i} - 10y \hat{j}) = -10x \hat{i} + 10y \hat{j}$. At point (2, 3) m, $x=2$

Q: What are the options for this this exam Physics question?

A. $(-20\hat{i}+30\hat{j})$ · B. $(20\hat{i}-30\hat{j})$ · C. $(20\hat{i}+45\hat{j})$ · D. $(-4\hat{i}+6\hat{j})$

Question

Q.37. The electric potential as a function of x, y is given by . The electric field at a point (2, 3) m is _______ V/m.

FirstInTest · Accepted Answer

The electric field $\vec{E}$ is related to the electric potential $V$ by $\vec{E} = -
abla V = -(\frac{\partial V}{\partial x} \hat{i} + \frac{\partial V}{\partial y} \hat{j})$. Given $V = 5(x^2 - y^2)$. $\frac{\partial V}{\partial x} = 5(2x) = 10x$. $\frac{\partial V}{\partial y} = 5(-2y) = -10y$. So, $\vec{E} = -(10x \hat{i} - 10y \hat{j}) = -10x \hat{i} + 10y \hat{j}$. At point (2, 3) m, $x=2$ and $y=3$. $\vec{E} = -10(2) \hat{i} + 10(3) \hat{j} = -20 \hat{i} + 30 \hat{j}$ V/m.

Answer

$(-20\hat{i}+30\hat{j})$

Answer

$(20\hat{i}-30\hat{j})$

Answer

$(20\hat{i}+45\hat{j})$

Answer

$(-4\hat{i}+6\hat{j})$

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