Q.37. A displacement current of 4.0 A can be set up in the space between two parallel plates of 6 capacitor. The rate of change of potential difference across the plates of the capacitor is nearly V/s. The value of is

Sol. $I_C = C \frac{dV}{dt}$. Given $I_C = 4.0 A$, $C = 6 \mu F = 6 \times 10^{-6} F$. $4 = (6 \times 10^{-6}) (\alpha \times 10^6)$. $4 = 6\alpha$. $\alpha = \frac{4}{6} = \frac{2}{3} \approx 0.67$.

What is the correct answer for this exam Physics Q37?

The correct answer is B. Sol. $I_C = C \frac{dV}{dt}$. Given $I_C = 4.0 A$, $C = 6 \mu F = 6 \times 10^{-6} F$. $4 = (6 \times 10^{-6}) (\alpha \times 10^6)$. $4 = 6\alpha$. $\alpha = \frac{4}{6} = \frac{2}{3} \approx 0.67$.

Q.37. A displacement current of 4.0 A can be set up in the space between two parallel plates of 6 capacitor. The rate of change of potential difference across the plates of the capacitor is nearly…

The correct answer is B. Sol. $I_C = C \frac{dV}{dt}$. Given $I_C = 4.0 A$, $C = 6 \mu F = 6 \times 10^{-6} F$. $4 = (6 \times 10^{-6}) (\alpha \times 10^6)$. $4 = 6\alpha$. $\alpha = \frac{4}{6} = \frac{2}{3} \approx 0.67$.

What are the options for this this exam Physics question?

A. 58 · B. 67 · C. 82 · D. 75

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Q.37. A displacement current of 4.0 A can be set up in the space between two parallel plates of 6 $\mu F$ capacitor. The rate of change of potential difference across the plates of the capacitor is nearly $\alpha \times 10^6$ V/s. The value of $\alpha$ is

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