JEE MainPhysicsNumerical
Q.48. The energy released when $\frac{7}{17.13}$ kg of $^7Li$ is converted into $^4He$ by proton bombardment is $\alpha \times 10^{32}$ eV. The value of $\alpha$ is ________ (Nearest integer) (Mass of $^7Li = 7.0183$ u, mass of $^4He = 4.004$ u, mass of proton $= 1.008$ u and 1 u $= 931$ MeV/c$^2$ and Avogadro number $= 6.0 \times 10^{23}$)

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