Q.69. Consider the following reactions. Total number of electrons in the bonds and lone pair of ele

Q: What is the correct answer for this exam Chemistry Q69?

The correct answer is 18. Sol. The reaction sequence is as follows:1. Glucose ($CHO(CHOH)_4CH_2OH$) reacts with $HI/\Delta$ (Red P/HI reduction) to form n-hexane ($CH_3-CH_2-CH_2-CH_2-CH_2-CH_3$).2. n-hexane reacts with $V_2O_5/10-20 atm/773 K$ (aromatization) to form benzene.3. Benzene reacts with Benzoyl chloride ($Ph-COCl$) in the presence of anhydrous $AlCl_3$ (Friedel-Crafts acylation) to form benzophenone ($Ph-CO-Ph$

Q: Q.69. Consider the following reactions. Total number of electrons in the bonds and lone pair of electrons in the product (X) is:[Figure: Reaction sequence starting from Glucose (). Step 1: Glucose…

The correct answer is 18. Sol. The reaction sequence is as follows:1. Glucose ($CHO(CHOH)_4CH_2OH$) reacts with $HI/\Delta$ (Red P/HI reduction) to form n-hexane ($CH_3-CH_2-CH_2-CH_2-CH_2-CH_3$).2. n-hexane reacts with $V_2O_5/10-20 atm/773 K$ (aromatization) to form benzene.3. Benzene reacts with Benzoyl chloride ($Ph-COCl$) in the presence of anhydrous $AlCl_3$ (Friedel-Crafts acylation) to form benzophenone ($Ph-CO-Ph$

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Q.69. Consider the following reactions. Total number of electrons in the  bonds and lone pair of electrons in the product (X) is:[Figure: Reaction sequence starting from Glucose (). Step 1: Glucose reacts with . Step 2: The product from step 1 reacts with  to form an intermediate. Step 3: This intermediate reacts with Benzoyl chloride/Anhyd.  to form the final product (X).]

FirstInTest · Accepted Answer

Sol. The reaction sequence is as follows:1. Glucose ($CHO(CHOH)_4CH_2OH$) reacts with $HI/\Delta$ (Red P/HI reduction) to form n-hexane ($CH_3-CH_2-CH_2-CH_2-CH_2-CH_3$).2. n-hexane reacts with $V_2O_5/10-20 atm/773 K$ (aromatization) to form benzene.3. Benzene reacts with Benzoyl chloride ($Ph-COCl$) in the presence of anhydrous $AlCl_3$ (Friedel-Crafts acylation) to form benzophenone ($Ph-CO-Ph$).So, the final product (X) is benzophenone.Benzophenone ($C_6H_5-CO-C_6H_5$) has two benzene rings and one carbonyl group.Each benzene ring has 3 $\pi$ bonds, so $2 	imes 3 = 6$ $\pi$ bonds.The carbonyl group ($C=O$) has 1 $\pi$ bond.Total $\pi$ bonds = $6 + 1 = 7$.The oxygen atom in the carbonyl group has 2 lone pairs of electrons.Total lone pair electrons = $2 	imes 2 = 4$.Total electrons in $\pi$ bonds and lone pairs = $(7 	imes 2) + 4 = 14 + 4 = 18$.

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