Q.68. The number of compounds from the following which can undergo reaction with to give respective

Q: What is the correct answer for this exam Chemistry Q68?

The correct answer is 3. Sol. The reaction with $Br_2/KOH/(alcoholic)$ refers to the Hoffmann bromamide degradation, which converts primary amides to primary amines. The Gabriel phthalimide synthesis is used for the preparation of primary amines.Therefore, we are looking for compounds that are primary amines. Let's analyze the given compounds: (i) Aniline ($Ph-NH_2$): Primary amine. Can be prepared by Gabriel phthalimide

Q: Q.68. The number of compounds from the following which can undergo reaction with to give respective products and these respective products can also be obtained separately by Gabriel phthalimide…

The correct answer is 3. Sol. The reaction with $Br_2/KOH/(alcoholic)$ refers to the Hoffmann bromamide degradation, which converts primary amides to primary amines. The Gabriel phthalimide synthesis is used for the preparation of primary amines.Therefore, we are looking for compounds that are primary amines. Let's analyze the given compounds: (i) Aniline ($Ph-NH_2$): Primary amine. Can be prepared by Gabriel phthalimide

Question

Q.68. The number of compounds from the following which can undergo reaction with  to give respective products and these respective products can also be obtained separately by Gabriel phthalimide reaction is: [Figure: Six organic compounds are shown: (i) Aniline, (ii) Benzylamine, (iii) Methylamine, (iv) N-methylpropanamide, (v) N-methylaniline, (vi) N-ethylaniline.]

FirstInTest · Accepted Answer

Sol. The reaction with $Br_2/KOH/(alcoholic)$ refers to the Hoffmann bromamide degradation, which converts primary amides to primary amines. The Gabriel phthalimide synthesis is used for the preparation of primary amines.Therefore, we are looking for compounds that are primary amines. Let's analyze the given compounds: (i) Aniline ($Ph-NH_2$): Primary amine. Can be prepared by Gabriel phthalimide synthesis. (ii) Benzylamine ($Ph-CH_2-NH_2$): Primary amine. Can be prepared by Gabriel phthalimide synthesis. (iii) Methylamine ($CH_3-NH_2$): Primary amine. Can be prepared by Gabriel phthalimide synthesis. (iv) N-methylpropanamide ($CH_3-CH_2-CO-NH-CH_3$): This is a secondary amide. Hoffmann bromamide degradation converts primary amides to primary amines. This compound will not undergo Hoffmann bromamide degradation to give a primary amine. (v) N-methylaniline ($Ph-NH-CH_3$): Secondary amine. Cannot be prepared by Gabriel phthalimide synthesis. (vi) N-ethylaniline ($Ph-NH-CH_2-CH_3$): Secondary amine. Cannot be prepared by Gabriel phthalimide synthesis.So, the compounds that fit the criteria are Aniline, Benzylamine, and Methylamine. The number of such compounds is 3.

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