Q.52. What is the energy (in J atom) required for the following process ? Li(g) Li(g) + e (Take the

Q: What is the correct answer for this exam Chemistry Q52?

The correct answer is C. The process Li$^{2+}$(g) $\rightarrow$ Li$^{3+}$(g) + e represents the ionization of Li$^{2+}$ to Li$^{3+}$. This is equivalent to removing the last electron from a hydrogen-like ion with atomic number $Z=3$ (for Lithium). The energy of an electron in a hydrogen-like species is given by $E_n = -E_H \frac{Z^2}{n^2}$, where $E_H$ is the ionization energy of hydrogen in its ground state. For the last

Q: Q.52. What is the energy (in J atom) required for the following process ? Li(g) Li(g) + e (Take the ionization energy for the H atom in the ground state as J atom)

The correct answer is C. The process Li$^{2+}$(g) $\rightarrow$ Li$^{3+}$(g) + e represents the ionization of Li$^{2+}$ to Li$^{3+}$. This is equivalent to removing the last electron from a hydrogen-like ion with atomic number $Z=3$ (for Lithium). The energy of an electron in a hydrogen-like species is given by $E_n = -E_H \frac{Z^2}{n^2}$, where $E_H$ is the ionization energy of hydrogen in its ground state. For the last

Q: What are the options for this this exam Chemistry question?

A. 72 \times 10^{-18} · B. 962 \times 10^{-18} · C. 962 \times 10^{-17} · D. 54 \times 10^{-17}

Question

Q.52. What is the energy (in J atom) required for the following process ? Li(g)  Li(g) + e (Take the ionization energy for the H atom in the ground state as  J atom)

FirstInTest · Accepted Answer

The process Li$^{2+}$(g) $ightarrow$ Li$^{3+}$(g) + e represents the ionization of Li$^{2+}$ to Li$^{3+}$. This is equivalent to removing the last electron from a hydrogen-like ion with atomic number $Z=3$ (for Lithium). The energy of an electron in a hydrogen-like species is given by $E_n = -E_H \frac{Z^2}{n^2}$, where $E_H$ is the ionization energy of hydrogen in its ground state. For the last electron in Li$^{2+}$, it is in the $n=1$ state. The energy required to remove this electron (ionization energy) is $E = E_H Z^2$. Given $E_H = 2.18 	imes 10^{-18}$ J atom$^{-1}$ and $Z=3$. So, $E = (2.18 	imes 10^{-18}) 	imes (3)^2 = 2.18 	imes 10^{-18} 	imes 9 = 19.62 	imes 10^{-18}$ J atom$^{-1} = 1.962 	imes 10^{-17}$ J atom$^{-1}$.

Answer

72 	imes 10^{-18}

Answer

962 	imes 10^{-18}

Answer

962 	imes 10^{-17}

Answer

54 	imes 10^{-17}

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