Arrange the following isoelectronic species in order of increasing ionic radii: N³⁻, O²⁻, F⁻, Na⁺, M

Q: What is the correct answer for CBS11?

The correct answer is A. For isoelectronic species, ionic radii decrease with increasing positive nuclear charge (or decreasing negative charge). All these species have 10 electrons. The nuclear charges are Al(13), Mg(12), Na(11), F(9), O(8), N(7). Therefore, the order of increasing ionic radii is Al³⁺ < Mg²⁺ < Na⁺ < F⁻ < O²⁻ < N³⁻.

Q: Arrange the following isoelectronic species in order of increasing ionic radii: N³⁻, O²⁻, F⁻, Na⁺, Mg²⁺, Al³⁺.

The correct answer is A. For isoelectronic species, ionic radii decrease with increasing positive nuclear charge (or decreasing negative charge). All these species have 10 electrons. The nuclear charges are Al(13), Mg(12), Na(11), F(9), O(8), N(7). Therefore, the order of increasing ionic radii is Al³⁺ < Mg²⁺ < Na⁺ < F⁻ < O²⁻ < N³⁻.

Q: What are the options for this CBS11 question?

A. Al³⁺ < Mg²⁺ < Na⁺ < F⁻ < O²⁻ < N³⁻ · B. N³⁻ < O²⁻ < F⁻ < Na⁺ < Mg²⁺ < Al³⁺ · C. F⁻ < O²⁻ < N³⁻ < Al³⁺ < Mg²⁺ < Na⁺ · D. Na⁺ < Mg²⁺ < Al³⁺ < F⁻ < O²⁻ < N³⁻

Question

Arrange the following isoelectronic species in order of increasing ionic radii: N³⁻, O²⁻, F⁻, Na⁺, Mg²⁺, Al³⁺.

FirstInTest · Accepted Answer

For isoelectronic species, ionic radii decrease with increasing positive nuclear charge (or decreasing negative charge). All these species have 10 electrons. The nuclear charges are Al(13), Mg(12), Na(11), F(9), O(8), N(7). Therefore, the order of increasing ionic radii is Al³⁺ < Mg²⁺ < Na⁺ < F⁻ < O²⁻ < N³⁻.

Answer

Al³⁺ < Mg²⁺ < Na⁺ < F⁻ < O²⁻ < N³⁻

Answer

N³⁻ < O²⁻ < F⁻ < Na⁺ < Mg²⁺ < Al³⁺

Answer

F⁻ < O²⁻ < N³⁻ < Al³⁺ < Mg²⁺ < Na⁺

Answer

Na⁺ < Mg²⁺ < Al³⁺ < F⁻ < O²⁻ < N³⁻

Related Questions

More from CBS11

Browse Engineering Questions by Subject

Practice Other Engineering Exams

Practice More CBS11 Questions