Q42. If the radius of a sphere is increased by 50%. then its surface area will increase by:

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FirstInTest · Accepted Answer

Correct answer: B. Let the original radius be r. So, the surface area of the sphere = 4πr² ....(1). Since, the radius is increased by 50% then new radius = 1.5r. Therefore the new surface area of the sphere will be = 4π(1.5)² = 2.25 × 4πr² ...(2). Therefore, the required percentage = (2.25×4πr² - 4πr²) / (4πr²) x 100 = 125%

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