Q7. When we draw the variation of the potential energy of a pair of nucleons with their separations,

Q: What is the correct answer for CUET UG Physics Q7?

The correct answer is A. The force (F) between nucleons is related to their potential energy (U) by F = -dU/dr. From the given graph, we can analyze the slope (dU/dr): 1. For separation r < 0.8 fm (approximately point r₀ on the x-axis, where potential energy is minimum), the potential energy rapidly increases as r decreases, meaning the slope dU/dr is negative and steep. Therefore, F = -dU/dr is positive, indicating a s

Q: Q7. When we draw the variation of the potential energy of a pair of nucleons with their separations, then A +100 Repulsive MeV B 0 D Attractive -100 Το 1 2 3 4 r(fm) (a) the force is attractive when…

The correct answer is A. The force (F) between nucleons is related to their potential energy (U) by F = -dU/dr. From the given graph, we can analyze the slope (dU/dr): 1. For separation r < 0.8 fm (approximately point r₀ on the x-axis, where potential energy is minimum), the potential energy rapidly increases as r decreases, meaning the slope dU/dr is negative and steep. Therefore, F = -dU/dr is positive, indicating a s

Q: What are the options for this CUET UG Physics question?

A. the force is attractive when separation between them is greater than 0.8 fm · B. the force is repulsive when separation between them is greater than O.S fm · C. the force is attractive when separation between them is less than 0.8 fm · D. the force is independent of their separation.

Question

Q7. When we draw the variation of the potential energy of a pair of nucleons with their separations, then
A
+100
Repulsive
MeV
B
0
D
Attractive
-100
Το 1
2
3
4
r(fm)
(a) the force is attractive when separation between
them is greater than 0.8 fm
(b) the force is repulsive when separation between
them is greater than O.S fm
(c) the force is attractive when separation between
them is less than 0.8 fm
(d) the force is independent of their separation.

FirstInTest · Accepted Answer

The force (F) between nucleons is related to their potential energy (U) by F = -dU/dr. From the given graph, we can analyze the slope (dU/dr): 
1.  For separation r < 0.8 fm (approximately point r₀ on the x-axis, where potential energy is minimum), the potential energy rapidly increases as r decreases, meaning the slope dU/dr is negative and steep. Therefore, F = -dU/dr is positive, indicating a strong repulsive force. 
2.  For separation r > 0.8 fm, the potential energy decreases (becomes more negative) and then approaches zero as r increases, meaning the slope dU/dr is positive. Therefore, F = -dU/dr is negative, indicating an attractive force. 
3.  At r ≈ 0.8 fm, the potential energy is at its minimum (point D), where the slope dU/dr = 0, meaning the net force is zero. 
Thus, the force is attractive when the separation between nucleons is greater than 0.8 fm, which corresponds to option (a).

Answer

the force is attractive when separation between them is greater than 0.8 fm

Answer

the force is repulsive when separation between them is greater than O.S fm

Answer

the force is attractive when separation between them is less than 0.8 fm

Answer

the force is independent of their separation.

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