Q5. Two electrons are moving with different kinetic energies. If 1st electron is moving with kinetic

Q: What is the correct answer for CUET UG Physics Q5?

The correct answer is c. The de Broglie wavelength (λ) of a particle is given by the formula λ = h/p, where h is Planck's constant and p is the momentum of the particle. The kinetic energy (K) of a particle is related to its momentum by K = p²/(2m), which means p = √(2mK). Substituting this into the de Broglie wavelength formula, we get λ = h / √(2mK). For two electrons (which have the same mass, m), the ratio of their de

Q: Q5. Two electrons are moving with different kinetic energies. If 1st electron is moving with kinetic energy k and the 2nd electron with kinetic energy 4k, the ratio of their de Broglie wavelengths…

The correct answer is c. The de Broglie wavelength (λ) of a particle is given by the formula λ = h/p, where h is Planck's constant and p is the momentum of the particle. The kinetic energy (K) of a particle is related to its momentum by K = p²/(2m), which means p = √(2mK). Substituting this into the de Broglie wavelength formula, we get λ = h / √(2mK). For two electrons (which have the same mass, m), the ratio of their de

Q: What are the options for this CUET UG Physics question?

A. 1:2 · B. 1:4 · C. 2:1 · D. 4:1

Question

Q5. Two electrons are moving with different kinetic energies. If 1st electron is moving with kinetic energy k and the 2nd electron with kinetic energy 4k, the ratio of their de Broglie wavelengths will be respectively:
(a) 1:2
(b) 1:4
(c) 2:1
(d) 4:1

FirstInTest · Accepted Answer

The de Broglie wavelength (λ) of a particle is given by the formula λ = h/p, where h is Planck's constant and p is the momentum of the particle. The kinetic energy (K) of a particle is related to its momentum by K = p²/(2m), which means p = √(2mK). Substituting this into the de Broglie wavelength formula, we get λ = h / √(2mK). For two electrons (which have the same mass, m), the ratio of their de Broglie wavelengths is λ₁/λ₂ = [h / √(2mK₁)] / [h / √(2mK₂)] = √(K₂/K₁). Given K₁ = k and K₂ = 4k, the ratio becomes λ₁/λ₂ = √(4k/k) = √4 = 2. Therefore, the ratio of their de Broglie wavelengths is 2:1.

Answer

1:2

Answer

1:4

Answer

2:1

Answer

4:1

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