Q46. The bottom of a container is a 6 cm thick glass (μ = 1.5) slab. The container contains a thick

Q: What is the correct answer for CUET UG Physics Q46?

The correct answer is D. The apparent shift (or normal shift) when viewing an object through multiple layers is given by: Shift = Σ [t_i * (1 - 1/μ_i)]. Here, the scratch is at the very bottom, so light from it travels through the glass layer (t=6 cm, μ=1.5) and then through the water layer (t_w=4 cm, μ_w=1.33). The total shift is: Shift = t_glass(1 - 1/μ_glass) + t_water(1 - 1/μ_water) = 6(1 - 1/1.5) + 4(1 - 1/1.33) = 6(

Q: Q46. The bottom of a container is a 6 cm thick glass (μ = 1.5) slab. The container contains a thick layer of water (μ_w = 1.33), 4 cm on top of the glass. What is the apparent position of a scratch…

The correct answer is D. The apparent shift (or normal shift) when viewing an object through multiple layers is given by: Shift = Σ [t_i * (1 - 1/μ_i)]. Here, the scratch is at the very bottom, so light from it travels through the glass layer (t=6 cm, μ=1.5) and then through the water layer (t_w=4 cm, μ_w=1.33). The total shift is: Shift = t_glass(1 - 1/μ_glass) + t_water(1 - 1/μ_water) = 6(1 - 1/1.5) + 4(1 - 1/1.33) = 6(

Q: What are the options for this CUET UG Physics question?

A. 1 cm · B. 2 cm · C. 3.5 cm · D. 3 cm

Question

Q46. The bottom of a container is a 6 cm thick glass (μ = 1.5) slab. The container contains a thick layer of water (μ_w = 1.33), 4 cm on top of the glass. What is the apparent position of a scratch on the outer surface of the bottom of the glass slab when viewed through the container?

FirstInTest · Accepted Answer

The apparent shift (or normal shift) when viewing an object through multiple layers is given by: Shift = Σ [t_i * (1 - 1/μ_i)]. Here, the scratch is at the very bottom, so light from it travels through the glass layer (t=6 cm, μ=1.5) and then through the water layer (t_w=4 cm, μ_w=1.33). The total shift is: Shift = t_glass(1 - 1/μ_glass) + t_water(1 - 1/μ_water) = 6(1 - 1/1.5) + 4(1 - 1/1.33) = 6(1 - 2/3) + 4(1 - 0.7518) = 6(1/3) + 4(0.2482) = 2 + 0.9928 ≈ 3 cm. This shift represents how much the apparent position is raised from the actual position. So, the apparent position of the scratch would be 3 cm from the outer bottom surface (i.e., it appears to be 3 cm higher than its actual position).

Answer

1 cm

Answer

2 cm

Answer

3.5 cm

Answer

3 cm

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