Q43. A hot wire voltmeter measures the voltage across the inductor, the capacitor and the resistor a

Q: What is the correct answer for CUET UG Physics Q43?

The correct answer is c. In a series LCR circuit, the current (I) is the same through all components. We are given the voltage across the resistor (V_R) and the resistance (R).Given: V_R = 50 V, R = 100 Ω.According to Ohm's law, the current through the resistor is I = V_R / R.I = 50 V / 100 Ω = 0.5 A.The voltages across the inductor (V_L = 150 V) and capacitor (V_C = 100 V) are consistent with this current, and the fact t

Q: Q43. A hot wire voltmeter measures the voltage across the inductor, the capacitor and the resistor as 150 V, 100 V and 50 V across a series, LCR circuit. If resistance is 100 Ω, the current in the…

The correct answer is c. In a series LCR circuit, the current (I) is the same through all components. We are given the voltage across the resistor (V_R) and the resistance (R).Given: V_R = 50 V, R = 100 Ω.According to Ohm's law, the current through the resistor is I = V_R / R.I = 50 V / 100 Ω = 0.5 A.The voltages across the inductor (V_L = 150 V) and capacitor (V_C = 100 V) are consistent with this current, and the fact t

Q: What are the options for this CUET UG Physics question?

A. 1.5 A · B. 1 A · C. 0.5 A · D. 0.7 A

Question

Q43. A hot wire voltmeter measures the voltage across the inductor, the capacitor and the resistor as 150 V, 100 V and 50 V across a series, LCR circuit. If resistance is 100 Ω, the current in the circuit is:
(a) 1.5 A
(b) 1 A
(c) 0.5 A
(d) 0.7 A

FirstInTest · Accepted Answer

In a series LCR circuit, the current (I) is the same through all components. We are given the voltage across the resistor (V_R) and the resistance (R).Given: V_R = 50 V, R = 100 Ω.According to Ohm's law, the current through the resistor is I = V_R / R.I = 50 V / 100 Ω = 0.5 A.The voltages across the inductor (V_L = 150 V) and capacitor (V_C = 100 V) are consistent with this current, and the fact that V_L > V_C indicates the circuit is inductive (the net reactive voltage V_L - V_C = 150 - 100 = 50 V). The total voltage across the circuit would be V = √(V_R² + (V_L - V_C)²) = √(50² + 50²) = 50√2 V.

Answer

1.5 A

Answer

1 A

Answer

0.5 A

Answer

0.7 A

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