Q42. A plane electromagnetic wave of frequency 50 MHz travels in free space along the x-direction. A

Q: What is the correct answer for CUET UG Physics Q42?

The correct answer is a. For a plane electromagnetic wave propagating in free space, the magnitudes of the electric field (E) and magnetic field (B) are related by the equation E = cB, where c is the speed of light in free space (c ≈ 3 × 10⁸ m/s). Given the magnitude of the electric field E = 9.3 V/m. We can calculate the magnitude of the magnetic field: B = E/c = 9.3 V/m / (3 × 10⁸ m/s) = 3.1 × 10⁻⁸ T. For an electromagn

Q: Q42. A plane electromagnetic wave of frequency 50 MHz travels in free space along the x-direction. At a particular point in space and time E = 9.3 jVm-1. What is B at this point? (a) (3.1 ×…

The correct answer is a. For a plane electromagnetic wave propagating in free space, the magnitudes of the electric field (E) and magnetic field (B) are related by the equation E = cB, where c is the speed of light in free space (c ≈ 3 × 10⁸ m/s). Given the magnitude of the electric field E = 9.3 V/m. We can calculate the magnitude of the magnetic field: B = E/c = 9.3 V/m / (3 × 10⁸ m/s) = 3.1 × 10⁻⁸ T. For an electromagn

Q: What are the options for this CUET UG Physics question?

A. (3.1 × 10⁻⁸k)T · B. (3.1 x 10⁻⁸i)Τ · C. (3.1 x 10⁸k)T · D. (3.1 x 10⁻⁸)T

Question

Q42. A plane electromagnetic wave of frequency 50 MHz travels in free space along the x-direction. At a particular point in space and time E = 9.3 jVm-1. What is B at this point?
(a) (3.1 × 10-8k)T
(b) (3.1 x 10-81)Τ
(c) (3.1 x 108k)T
(d) (3.1 x 10-8)T

FirstInTest · Accepted Answer

For a plane electromagnetic wave propagating in free space, the magnitudes of the electric field (E) and magnetic field (B) are related by the equation E = cB, where c is the speed of light in free space (c ≈ 3 × 10⁸ m/s). Given the magnitude of the electric field E = 9.3 V/m. We can calculate the magnitude of the magnetic field: B = E/c = 9.3 V/m / (3 × 10⁸ m/s) = 3.1 × 10⁻⁸ T. For an electromagnetic wave, the electric field (E), magnetic field (B), and the direction of propagation (k̂) are mutually perpendicular and related by the right-hand rule, specifically k̂ = Ê × B̂. The wave travels along the x-direction (k̂ = î), and the electric field is in the y-direction (Ê = ĵ). So, we need î = ĵ × B̂. According to the cross product rules (î = ĵ × k̂), the magnetic field B must be in the z-direction (B̂ = k̂). Therefore, the magnetic field at this point is B = (3.1 × 10⁻⁸ k̂) T. Options (b), (c), and (d) are incorrect due to wrong direction, incorrect magnitude, or incorrect units.

Answer

(3.1 × 10⁻⁸k)T

Answer

(3.1 x 10⁻⁸i)Τ

Answer

(3.1 x 10⁸k)T

Answer

(3.1 x 10⁻⁸)T

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