Q40. Match List - I with List - II.
List - I
(A) Electric Field
(B) Electric Flux
(C) Electric Dipol

Q: What is the correct answer for CUET UG Physics Q40?

The correct answer is a. To match the physical quantities with their dimensional formulas: (A) Electric Field (E): Electric field is defined as Force per unit charge (E = F/q). The dimensions of Force are [MLT⁻²] and Charge are [AT]. So, E = [MLT⁻²] / [AT] = [MLT⁻³A⁻¹]. This matches (IV). (B) Electric Flux (ΦE): Electric flux is the product of electric field and area (ΦE = E⋅A). The dimensions of Electric Field are [MLT⁻³

Q: Q40. Match List - I with List - II. List - I (A) Electric Field (B) Electric Flux (C) Electric Dipole Moment (D) Area Vector Element List - II (I) [LTA] (II) [L²] (III) [ML³ T⁻³ A⁻¹] (IV) [MLT⁻³…

The correct answer is a. To match the physical quantities with their dimensional formulas: (A) Electric Field (E): Electric field is defined as Force per unit charge (E = F/q). The dimensions of Force are [MLT⁻²] and Charge are [AT]. So, E = [MLT⁻²] / [AT] = [MLT⁻³A⁻¹]. This matches (IV). (B) Electric Flux (ΦE): Electric flux is the product of electric field and area (ΦE = E⋅A). The dimensions of Electric Field are [MLT⁻³

Q: What are the options for this CUET UG Physics question?

A. (A)-(IV), (B)-(III), (C)-(I), (D)-(II) · B. (A)-(IV), (B)-(III), (C)-(II), (D)-(I) · C. (A)-(III), (B)-(IV), (C)-(I), (D)-(II) · D. (A)-(II), (B)-(III), (C)-(I), (D)-(IV)

Question

Q40. Match List - I with List - II.
List - I
(A) Electric Field
(B) Electric Flux
(C) Electric Dipole Moment
(D) Area Vector Element
List - II
(I) [LTA]
(II) [L²]
(III) [ML³ T⁻³ A⁻¹]
(IV) [MLT⁻³ A⁻¹]
Choose the correct answer from the options given below:
(a) (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
(b) (A)-(IV), (B)-(III), (C)-(II), (D)-(I)
(c) (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
(d) (A)-(II), (B)-(III), (C)-(I), (D)-(IV)

FirstInTest · Accepted Answer

To match the physical quantities with their dimensional formulas:
(A) Electric Field (E): Electric field is defined as Force per unit charge (E = F/q). The dimensions of Force are [MLT⁻²] and Charge are [AT]. So, E = [MLT⁻²] / [AT] = [MLT⁻³A⁻¹]. This matches (IV).
(B) Electric Flux (ΦE): Electric flux is the product of electric field and area (ΦE = E⋅A). The dimensions of Electric Field are [MLT⁻³A⁻¹] and Area are [L²]. So, ΦE = [MLT⁻³A⁻¹] × [L²] = [ML³T⁻³A⁻¹]. This matches (III).
(C) Electric Dipole Moment (p): Electric dipole moment is defined as charge times separation distance (p = qd). The dimensions of Charge are [AT] and distance are [L]. So, p = [AT] × [L] = [LTA]. This matches (I).
(D) Area Vector Element (dA): An area vector simply represents an area, so its dimension is [L²]. This matches (II).
Therefore, the correct mapping is (A)-(IV), (B)-(III), (C)-(I), (D)-(II), which corresponds to option (a).

Answer

(A)-(IV), (B)-(III), (C)-(I), (D)-(II)

Answer

(A)-(IV), (B)-(III), (C)-(II), (D)-(I)

Answer

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Answer

(A)-(II), (B)-(III), (C)-(I), (D)-(IV)

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