Q38. A ray of light passes through four transparent media with refractive index μ₁,μ2,µ3 and µ₁ show

Q: What is the correct answer for CUET UG Physics Q38?

The correct answer is C. When a ray of light passes through multiple parallel layers of different transparent media, Snell's Law applies at each interface. Snell's Law states that μ sin θ = constant, where μ is the refractive index of the medium and θ is the angle the ray makes with the normal to the surface. For the given setup, we have: μ₁ sin θ₁ = μ₂ sin θ₂ (at the interface between μ₁ and μ₂) μ₂ sin θ₂ = μ₃ sin θ₃ (a

Q: Q38. A ray of light passes through four transparent media with refractive index μ₁,μ2,µ3 and µ₁ shown in figure. The surfaces of all media are parallel. If BC and DE are parallel, we must…

The correct answer is C. When a ray of light passes through multiple parallel layers of different transparent media, Snell's Law applies at each interface. Snell's Law states that μ sin θ = constant, where μ is the refractive index of the medium and θ is the angle the ray makes with the normal to the surface. For the given setup, we have: μ₁ sin θ₁ = μ₂ sin θ₂ (at the interface between μ₁ and μ₂) μ₂ sin θ₂ = μ₃ sin θ₃ (a

Q: What are the options for this CUET UG Physics question?

A. μ₁ = μ₄ · B. μ₂ = μ₃ · C. μ₂ = μ₄ · D. μ₁ = μ₃

Question

Q38. A ray of light passes through four transparent media with refractive index μ₁,μ2,µ3 and µ₁ shown in figure. The surfaces of all media are parallel. If BC and DE are parallel, we must have
A
μ
E
3
2
μι
(α) μ₁ = μα
(b) μ₂ = μ3
(C) μ₂ = μ4
(d) μ₁ = με

FirstInTest · Accepted Answer

When a ray of light passes through multiple parallel layers of different transparent media, Snell's Law applies at each interface. Snell's Law states that μ sin θ = constant, where μ is the refractive index of the medium and θ is the angle the ray makes with the normal to the surface. 
For the given setup, we have:
μ₁ sin θ₁ = μ₂ sin θ₂ (at the interface between μ₁ and μ₂)
μ₂ sin θ₂ = μ₃ sin θ₃ (at the interface between μ₂ and μ₃)
μ₃ sin θ₃ = μ₄ sin θ₄ (at the interface between μ₃ and μ₄)
Therefore, we can write: μ₁ sin θ₁ = μ₂ sin θ₂ = μ₃ sin θ₃ = μ₄ sin θ₄. 
The condition 'if BC and DE are parallel' refers to the light ray's path segments within medium μ₂ and medium μ₄, respectively. If these segments are parallel, it means the angle the light ray makes with the normal in medium μ₂ (θ₂) is equal to the angle it makes with the normal in medium μ₄ (θ₄). So, θ₂ = θ₄. 
Using Snell's Law for these two media: μ₂ sin θ₂ = μ₄ sin θ₄. 
Since θ₂ = θ₄, we can conclude that μ₂ = μ₄. This matches option (c).

Answer

μ₁ = μ₄

Answer

μ₂ = μ₃

Answer

μ₂ = μ₄

Answer

μ₁ = μ₃

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