Q38. A radioactive nucleus decays as given below:
ZPX → Z+1Q → R → Z-1R
Which particles are emitted

Q: What is the correct answer for CUET UG Physics Q38?

The correct answer is d. Let's analyze the changes in atomic number (Z) and mass number (A, represented by P) at each step of the radioactive decay: 1. **ZPX → Z+1Q:** In this step, the atomic number (Z) increases by 1, and the mass number (P) remains unchanged. This change is characteristic of **beta-minus (β⁻) decay**, where a neutron transforms into a proton, emitting an electron. 2. **Z+1Q → R:** The atomic number c

Q: Q38. A radioactive nucleus decays as given below: ZPX → Z+1Q → R → Z-1R Which particles are emitted in the sequence? (a) α, β, γ (b) β, γ, α (c) γ, α, β (d) β, α, γ

The correct answer is d. Let's analyze the changes in atomic number (Z) and mass number (A, represented by P) at each step of the radioactive decay: 1. **ZPX → Z+1Q:** In this step, the atomic number (Z) increases by 1, and the mass number (P) remains unchanged. This change is characteristic of **beta-minus (β⁻) decay**, where a neutron transforms into a proton, emitting an electron. 2. **Z+1Q → R:** The atomic number c

Q: What are the options for this CUET UG Physics question?

A. α, β, γ · B. β, γ, α · C. γ, α, β · D. β, α, γ

Question

Q38. A radioactive nucleus decays as given below:
ZPX → Z+1Q → R → Z-1R
Which particles are emitted in the sequence?
(a) α, β, γ
(b) β, γ, α
(c) γ, α, β
(d) β, α, γ

FirstInTest · Accepted Answer

Let's analyze the changes in atomic number (Z) and mass number (A, represented by P) at each step of the radioactive decay:
1.  **ZPX → Z+1Q:** In this step, the atomic number (Z) increases by 1, and the mass number (P) remains unchanged. This change is characteristic of **beta-minus (β⁻) decay**, where a neutron transforms into a proton, emitting an electron.
2.  **Z+1Q → R:** The atomic number changes from (Z+1) to R. Let's look at the next step's final state for R. Assuming R refers to the (mass number, atomic number) state of the nucleus after the second decay: (P-4, Z-1). This implies the atomic number decreased by 2 (from Z+1 to Z-1) and the mass number decreased by 4 (from P to P-4). These changes are characteristic of **alpha (α) decay**, where an alpha particle (⁴₂He) is emitted.
3.  **R → Z-1R:** Here, both the atomic number (Z-1) and the mass number (P-4) of the nucleus remain unchanged. This type of decay, which involves the emission of high-energy photons without altering the nucleus's composition, is **gamma (γ) decay**. The final product symbol (Z-1R) just indicates the state of the nucleus. Therefore, the sequence of emitted particles is β, α, γ, matching option (d).

Answer

α, β, γ

Answer

β, γ, α

Answer

γ, α, β

Answer

β, α, γ

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