Q38. A radioactive nucleus decays as given below:
Z_P^A → Z+1_Q^A → Z-1_R^(A-4) → Z-1_R^(A-4)
Which

Q: What is the correct answer for CUET UG Physics Q38?

The correct answer is d. Let's analyze each step of the decay chain:1. Z_P^A → Z+1_Q^A: - The mass number (A) remains unchanged. - The atomic number (Z) increases by 1 (from Z to Z+1). This transformation is characteristic of a beta-minus (β⁻) decay, where a neutron converts into a proton, emitting an electron (β⁻ particle) and an antineutrino. So, the first emitted particle is β.2. Z+1_Q^A → Z-1_R^(A-4):

Q: Q38. A radioactive nucleus decays as given below: Z_P^A → Z+1_Q^A → Z-1_R^(A-4) → Z-1_R^(A-4) Which particles are emitted in the sequence? (a) α, β, γ (b) β, γ, α (c) γ, α, β (d) β, α, γ

The correct answer is d. Let's analyze each step of the decay chain:1. Z_P^A → Z+1_Q^A: - The mass number (A) remains unchanged. - The atomic number (Z) increases by 1 (from Z to Z+1). This transformation is characteristic of a beta-minus (β⁻) decay, where a neutron converts into a proton, emitting an electron (β⁻ particle) and an antineutrino. So, the first emitted particle is β.2. Z+1_Q^A → Z-1_R^(A-4):

Q: What are the options for this CUET UG Physics question?

A. α, β, γ · B. β, γ, α · C. γ, α, β · D. β, α, γ

Question

Q38. A radioactive nucleus decays as given below:
Z_P^A → Z+1_Q^A → Z-1_R^(A-4) → Z-1_R^(A-4)
Which particles are emitted in the sequence?
(a) α, β, γ
(b) β, γ, α
(c) γ, α, β
(d) β, α, γ

FirstInTest · Accepted Answer

Let's analyze each step of the decay chain:1.  Z_P^A → Z+1_Q^A:    -   The mass number (A) remains unchanged.    -   The atomic number (Z) increases by 1 (from Z to Z+1).    This transformation is characteristic of a beta-minus (β⁻) decay, where a neutron converts into a proton, emitting an electron (β⁻ particle) and an antineutrino. So, the first emitted particle is β.2.  Z+1_Q^A → Z-1_R^(A-4):    -   The mass number (A) decreases by 4 (from A to A-4).    -   The atomic number (Z) decreases by 2 (from Z+1 to Z-1).    This transformation is characteristic of an alpha (α) decay, where an alpha particle (²⁴He nucleus) is emitted. So, the second emitted particle is α.3.  Z-1_R^(A-4) → Z-1_R^(A-4):    -   The mass number (A) remains unchanged.    -   The atomic number (Z) remains unchanged.    This indicates that the nucleus transitioned from an excited state to a lower energy state without changing its composition, which is characteristic of gamma (γ) emission. So, the third emitted particle is γ.Therefore, the sequence of emitted particles is β, α, γ.

Answer

α, β, γ

Answer

β, γ, α

Answer

γ, α, β

Answer

β, α, γ

Related Questionsin Physics

More from CUET UG

Browse CUET Questions by Subject

Practice More CUET UG Questions