Q37. Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, il

Q: What is the correct answer for CUET UG Physics Q37?

The correct answer is b. According to Einstein's photoelectric equation, the maximum kinetic energy (KE_max) of emitted electrons is given by KE_max = E_photon - Φ, where E_photon is the energy of the incident photon and Φ is the work function of the metal.Given work function Φ = 0.5 eV.For the first light source:Photon energy E_photon₁ = 1 eV.Maximum KE₁ = E_photon₁ - Φ = 1 eV - 0.5 eV = 0.5 eV.For the second light sourc

Q: Q37. Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, illuminate a metal of work function 0.5 eV. The ratio of the maximum KE of the emitted electrons will…

The correct answer is b. According to Einstein's photoelectric equation, the maximum kinetic energy (KE_max) of emitted electrons is given by KE_max = E_photon - Φ, where E_photon is the energy of the incident photon and Φ is the work function of the metal.Given work function Φ = 0.5 eV.For the first light source:Photon energy E_photon₁ = 1 eV.Maximum KE₁ = E_photon₁ - Φ = 1 eV - 0.5 eV = 0.5 eV.For the second light sourc

Q: What are the options for this CUET UG Physics question?

A. 1:5 · B. 1:4 · C. 1:2 · D. 1:1

Question

Q37. Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively, illuminate a metal of work function 0.5 eV. The ratio of the maximum KE of the emitted electrons will be:
(a) 1:5
(b) 1:4
(c) 1:2
(d) 1:1

FirstInTest · Accepted Answer

According to Einstein's photoelectric equation, the maximum kinetic energy (KE_max) of emitted electrons is given by KE_max = E_photon - Φ, where E_photon is the energy of the incident photon and Φ is the work function of the metal.Given work function Φ = 0.5 eV.For the first light source:Photon energy E_photon₁ = 1 eV.Maximum KE₁ = E_photon₁ - Φ = 1 eV - 0.5 eV = 0.5 eV.For the second light source:Photon energy E_photon₂ = 2.5 eV.Maximum KE₂ = E_photon₂ - Φ = 2.5 eV - 0.5 eV = 2.0 eV.The ratio of the maximum kinetic energies is KE₁ : KE₂ = 0.5 eV : 2.0 eV = 1 : 4.

Answer

1:5

Answer

1:4

Answer

1:2

Answer

1:1

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