Q37. If a match box of size 5 cm x 4 cm x 1 cm is filled with nuclear matter, what will be its expec

Q: What is the correct answer for CUET UG Physics Q37?

The correct answer is d. The mass (M) of an object is calculated by multiplying its volume (V) by its density (ρ): M = V × ρ. First, calculate the volume of the matchbox: V = length × width × height = 5 cm × 4 cm × 1 cm = 20 cm³. Next, convert this volume to cubic meters (m³): 20 cm³ = 20 × (10⁻² m)³ = 20 × 10⁻⁶ m³ = 2 × 10⁻⁵ m³. The given density of nuclear matter is ρ = 2.3 × 10¹⁷ kg m⁻³. Now, calculate the mass: M = (2

Q: Q37. If a match box of size 5 cm x 4 cm x 1 cm is filled with nuclear matter, what will be its expected mass? The density of the nuclear matter is approximately 2.3 × 10¹⁷ kg m⁻³. (a) 4.6 x 10¹²…

The correct answer is d. The mass (M) of an object is calculated by multiplying its volume (V) by its density (ρ): M = V × ρ. First, calculate the volume of the matchbox: V = length × width × height = 5 cm × 4 cm × 1 cm = 20 cm³. Next, convert this volume to cubic meters (m³): 20 cm³ = 20 × (10⁻² m)³ = 20 × 10⁻⁶ m³ = 2 × 10⁻⁵ m³. The given density of nuclear matter is ρ = 2.3 × 10¹⁷ kg m⁻³. Now, calculate the mass: M = (2

Q: What are the options for this CUET UG Physics question?

A. 4.6 x 10¹² mg · B. 4.6 × 10¹² µg · C. 4.6 x 10¹² g · D. 4.6 x 10¹² kg

Question

Q37. If a match box of size 5 cm x 4 cm x 1 cm is filled with nuclear matter, what will be its expected mass? The density of the nuclear matter is approximately 2.3 × 10¹⁷ kg m⁻³.
(a) 4.6 x 10¹² mg
(b) 4.6 × 10¹² µg
(c) 4.6 x 10¹² g
(d) 4.6 x 10¹² kg

FirstInTest · Accepted Answer

The mass (M) of an object is calculated by multiplying its volume (V) by its density (ρ): M = V × ρ. First, calculate the volume of the matchbox: V = length × width × height = 5 cm × 4 cm × 1 cm = 20 cm³. Next, convert this volume to cubic meters (m³): 20 cm³ = 20 × (10⁻² m)³ = 20 × 10⁻⁶ m³ = 2 × 10⁻⁵ m³. The given density of nuclear matter is ρ = 2.3 × 10¹⁷ kg m⁻³. Now, calculate the mass: M = (2 × 10⁻⁵ m³) × (2.3 × 10¹⁷ kg m⁻³) = (2 × 2.3) × 10^(⁻⁵⁺¹⁷) kg = 4.6 × 10¹² kg. Therefore, a matchbox filled with nuclear matter would have an expected mass of 4.6 × 10¹² kg. Options (a), (b), and (c) are incorrect units or magnitudes, as they represent milligrams, micrograms, or grams, respectively.

Answer

4.6 x 10¹² mg

Answer

4.6 × 10¹² µg

Answer

4.6 x 10¹² g

Answer

4.6 x 10¹² kg

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