Q35. The current flowing through a wire as a function fo time is given as: I = 3t² + 2t + 5The charg

Q: What is the correct answer for CUET UG Physics Q35?

The correct answer is d. Current (I) is defined as the rate of flow of charge (dq/dt). To find the total charge (q) that flows through a cross-section of the wire over a time interval, we integrate the current function with respect to time.Given: I(t) = 3t² + 2t + 5.We need to find the charge flowing in the first 2 seconds, so the integration limits are from t = 0 s to t = 2 s.q = ∫ I(t) dt = ∫₀² (3t² + 2t + 5) dtq = [3t³

Q: Q35. The current flowing through a wire as a function fo time is given as: I = 3t² + 2t + 5The charge flowing through any cross-section of the wire in first 2 s is: (a) 5 C (b) 17 C (c) 16 C (d) 22 C

The correct answer is d. Current (I) is defined as the rate of flow of charge (dq/dt). To find the total charge (q) that flows through a cross-section of the wire over a time interval, we integrate the current function with respect to time.Given: I(t) = 3t² + 2t + 5.We need to find the charge flowing in the first 2 seconds, so the integration limits are from t = 0 s to t = 2 s.q = ∫ I(t) dt = ∫₀² (3t² + 2t + 5) dtq = [3t³

Q: What are the options for this CUET UG Physics question?

A. 5 C · B. 17 C · C. 16 C · D. 22 C

Question

Q35. The current flowing through a wire as a function fo time is given as: I = 3t² + 2t + 5The charge flowing through any cross-section of the wire in first 2 s is:
(a) 5 C
(b) 17 C
(c) 16 C
(d) 22 C

FirstInTest · Accepted Answer

Current (I) is defined as the rate of flow of charge (dq/dt). To find the total charge (q) that flows through a cross-section of the wire over a time interval, we integrate the current function with respect to time.Given: I(t) = 3t² + 2t + 5.We need to find the charge flowing in the first 2 seconds, so the integration limits are from t = 0 s to t = 2 s.q = ∫ I(t) dt = ∫₀² (3t² + 2t + 5) dtq = [3t³/3 + 2t²/2 + 5t]₀²q = [t³ + t² + 5t]₀²Now, evaluate the definite integral:q = (2³ + 2² + 5*2) - (0³ + 0² + 5*0)q = (8 + 4 + 10) - 0q = 22 C.Therefore, the charge flowing through the wire in the first 2 seconds is 22 C.

Answer

5 C

Answer

17 C

Answer

16 C

Answer

22 C

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