Q35. An electric dipole of dipole moment 5 x 10⁻⁶ Cm is placed in a uniform electric field of 10⁻² N

Q: What is the correct answer for CUET UG Physics Q35?

The correct answer is C. The torque (τ) experienced by an electric dipole placed in a uniform electric field is given by the vector cross product τ = p x E, where p is the electric dipole moment and E is the electric field. The magnitude of the torque is given by τ = pE sinθ, where θ is the angle between the dipole moment vector and the electric field vector. Given: Dipole moment p = 5 x 10⁻⁶ C·m. Electric field E = 10⁻²

Q: Q35. An electric dipole of dipole moment 5 x 10⁻⁶ Cm is placed in a uniform electric field of 10⁻² N/C making an angle of 30° with the direction of the field. The torque exerted by the electric field…

The correct answer is C. The torque (τ) experienced by an electric dipole placed in a uniform electric field is given by the vector cross product τ = p x E, where p is the electric dipole moment and E is the electric field. The magnitude of the torque is given by τ = pE sinθ, where θ is the angle between the dipole moment vector and the electric field vector. Given: Dipole moment p = 5 x 10⁻⁶ C·m. Electric field E = 10⁻²

Q: What are the options for this CUET UG Physics question?

A. 1 x 10⁻⁸ Nm · B. 1.5 x 10⁻⁸ Nm · C. 2.5 x 10⁻⁸ Nm · D. 5 x 10⁻⁸ Nm

Question

Q35. An electric dipole of dipole moment 5 x 10⁻⁶ Cm is placed in a uniform electric field of 10⁻² N/C making an angle of 30° with the direction of the field. The torque exerted by the electric field on the dipole is:
(a) 1 x 10⁻⁸ Nm
(b) 1.5 x 10⁻⁸ Nm
(c) 2.5 x 10⁻⁸ Nm
(d) 5 x 10⁻⁸ Nm

FirstInTest · Accepted Answer

The torque (τ) experienced by an electric dipole placed in a uniform electric field is given by the vector cross product τ = p x E, where p is the electric dipole moment and E is the electric field. The magnitude of the torque is given by τ = pE sinθ, where θ is the angle between the dipole moment vector and the electric field vector. 
Given: Dipole moment p = 5 x 10⁻⁶ C·m. Electric field E = 10⁻² N/C. Angle θ = 30°. 
Substitute the values into the formula: 
τ = (5 x 10⁻⁶ C·m) * (10⁻² N/C) * sin(30°) 
τ = (5 x 10⁻⁶ * 10⁻²) * (1/2) N·m 
τ = (5 x 10⁻⁸) * (0.5) N·m 
τ = 2.5 x 10⁻⁸ N·m. 
This matches option (c).

Answer

1 x 10⁻⁸ Nm

Answer

1.5 x 10⁻⁸ Nm

Answer

2.5 x 10⁻⁸ Nm

Answer

5 x 10⁻⁸ Nm

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