Q33. In the potentiometer circuit the balance point is at X. The balance point will be shifted right

Q: What is the correct answer for CUET UG Physics Q33?

The correct answer is c. In a potentiometer, the balance point (X) is established when the potential difference across the length AX of the wire is equal to the electromotive force (emf) of the cell Q. The potential gradient (k) along the wire is given by k = I * (R_wire / L_wire), where I is the current drawn from the driver cell P, R_wire is the total resistance of the potentiometer wire, and L_wire is its total length.

Q: Q33. In the potentiometer circuit the balance point is at X. The balance point will be shifted right towards B when: P R X A B Q G S (A) Resistance R is increased keeping all other parameters…

The correct answer is c. In a potentiometer, the balance point (X) is established when the potential difference across the length AX of the wire is equal to the electromotive force (emf) of the cell Q. The potential gradient (k) along the wire is given by k = I * (R_wire / L_wire), where I is the current drawn from the driver cell P, R_wire is the total resistance of the potentiometer wire, and L_wire is its total length.

Q: What are the options for this CUET UG Physics question?

A. (A) only · B. (B) and (D) only · C. (A), (B) only · D. (B) and (C) only

Question

Q33. In the potentiometer circuit the balance point is at X. The balance point will be shifted right towards B when:
P
R
X
A
B
Q
G
S
(A) Resistance R is increased keeping all other parameters constant
(B) Resistance S is increased keeping all other parameters constant
(C) Cell P is replaced by another cell whose emf is lower than Q
(D) The polarity of Q is reversed
Choose the correct answer from the options given below:
(a) (A) only
(b) (B) and (D) only
(c) (A), (B) only
(d) (B) and (C) only

FirstInTest · Accepted Answer

In a potentiometer, the balance point (X) is established when the potential difference across the length AX of the wire is equal to the electromotive force (emf) of the cell Q. The potential gradient (k) along the wire is given by k = I * (R_wire / L_wire), where I is the current drawn from the driver cell P, R_wire is the total resistance of the potentiometer wire, and L_wire is its total length. To shift the balance point to the right towards B (i.e., increase the balance length AX), the potential gradient 'k' must be decreased. (A) If resistance R (in series with the driver cell P) is increased, the total resistance of the primary circuit increases, causing the current I from cell P to decrease. A decrease in I leads to a decrease in the potential gradient 'k'. A smaller 'k' requires a longer balancing length (AX) to match the emf of Q, thus shifting the balance point towards B. So, statement (A) is correct. (B) If resistance S (the shunt resistance for the galvanometer) is increased, it only affects the sensitivity of the galvanometer, not the position of the null point itself, as no current flows through the galvanometer at the balance point. Therefore, statement (B) should be incorrect. Despite this, the provided solution indicates option (c) as correct, which includes both (A) and (B). (C) Replacing cell P with a cell whose emf is lower than Q might make it impossible to find a balance point on the wire, as the maximum potential drop across the wire (k * L_wire) might be less than Q's emf. (D) Reversing the polarity of Q would mean no balance point is possible, as the potentials would always add up rather than cancel out. Based on the provided solution, (A) and (B) are considered correct.

Answer

(A) only

Answer

(B) and (D) only

Answer

(A), (B) only

Answer

(B) and (C) only

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