Q31. In an AC generator when the plane of the armature is perpendicular to the magnetic field, what

Q: What is the correct answer for CUET UG Physics Q31?

The correct answer is d. In an AC generator, the magnetic flux (Φ) passing through a coil is given by Φ = BAcosθ, where B is the magnetic field strength, A is the area of the coil, and θ is the angle between the normal to the plane of the coil and the magnetic field. When the plane of the armature is perpendicular to the magnetic field, the normal to the coil's plane is parallel to the magnetic field, meaning θ = 0°. Sinc

Q: Q31. In an AC generator when the plane of the armature is perpendicular to the magnetic field, what will the magnitude of the magnetic flux passing through the coil and the emf induced in the coil…

The correct answer is d. In an AC generator, the magnetic flux (Φ) passing through a coil is given by Φ = BAcosθ, where B is the magnetic field strength, A is the area of the coil, and θ is the angle between the normal to the plane of the coil and the magnetic field. When the plane of the armature is perpendicular to the magnetic field, the normal to the coil's plane is parallel to the magnetic field, meaning θ = 0°. Sinc

Q: What are the options for this CUET UG Physics question?

A. Both the magnetic flux and the induced emf are maximum · B. Both the magnetic flux and the induced emf are zero · C. The magnetic flux is zero and the induced emf is maximum · D. The magnetic flux is maximum and the induced emf is zero

Question

Q31. In an AC generator when the plane of the armature is perpendicular to the magnetic field, what will the magnitude of the magnetic flux passing through the coil and the emf induced in the coil be?
(a) Both the magnetic flux and the induced emf are maximum
(b) Both the magnetic flux and the induced emf are zero
(c) The magnetic flux is zero and the induced emf is maximum
(d) The magnetic flux is maximum and the induced emf is zero

FirstInTest · Accepted Answer

In an AC generator, the magnetic flux (Φ) passing through a coil is given by Φ = BAcosθ, where B is the magnetic field strength, A is the area of the coil, and θ is the angle between the normal to the plane of the coil and the magnetic field. When the plane of the armature is perpendicular to the magnetic field, the normal to the coil's plane is parallel to the magnetic field, meaning θ = 0°. Since cos(0°) = 1, the magnetic flux Φ = BA, which is its maximum value. The induced emf (ε) is given by Faraday's law of electromagnetic induction as ε = -dΦ/dt. For a rotating coil, Φ = BAcos(ωt), so ε = -d/dt(BAcos(ωt)) = BAωsin(ωt). At the position where the plane is perpendicular to the magnetic field, ωt = 0°, and sin(0°) = 0. Therefore, the induced emf ε = 0. So, when the plane of the armature is perpendicular to the magnetic field, the magnetic flux is maximum, and the induced emf is zero. Options (a), (b), and (c) incorrectly describe the magnitudes of flux and induced emf at this specific orientation.

Answer

Both the magnetic flux and the induced emf are maximum

Answer

Both the magnetic flux and the induced emf are zero

Answer

The magnetic flux is zero and the induced emf is maximum

Answer

The magnetic flux is maximum and the induced emf is zero

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