Q30. A bubble in glass slab (μ = 1.5) when viewed from one side appears at 5 cm and 2 cm from others

Q: What is the correct answer for CUET UG Physics Q30?

The correct answer is C. When an object inside a denser medium is viewed normally from a rarer medium, its apparent depth (d_app) is less than its real depth (d_real). The relationship is given by d_app = d_real / μ, where μ is the refractive index of the denser medium. Let the total thickness of the glass slab be T. Let the real depth of the bubble from one side be d₁_real and from the other side be d₂_real. So, T = d₁_

Q: Q30. A bubble in glass slab (μ = 1.5) when viewed from one side appears at 5 cm and 2 cm from otherside, then the thickness of the glass slab is: (a) 2.5 cm (b) 7.5 cm (c) 10.5 cm (d) 17.5 cm

The correct answer is C. When an object inside a denser medium is viewed normally from a rarer medium, its apparent depth (d_app) is less than its real depth (d_real). The relationship is given by d_app = d_real / μ, where μ is the refractive index of the denser medium. Let the total thickness of the glass slab be T. Let the real depth of the bubble from one side be d₁_real and from the other side be d₂_real. So, T = d₁_

Q: What are the options for this CUET UG Physics question?

A. 2.5 cm · B. 7.5 cm · C. 10.5 cm · D. 17.5 cm

Question

Q30. A bubble in glass slab (μ = 1.5) when viewed from one side appears at 5 cm and 2 cm from otherside, then the thickness of the glass slab is:
(a) 2.5 cm
(b) 7.5 cm
(c) 10.5 cm
(d) 17.5 cm

FirstInTest · Accepted Answer

When an object inside a denser medium is viewed normally from a rarer medium, its apparent depth (d_app) is less than its real depth (d_real). The relationship is given by d_app = d_real / μ, where μ is the refractive index of the denser medium. 
Let the total thickness of the glass slab be T. Let the real depth of the bubble from one side be d₁_real and from the other side be d₂_real. So, T = d₁_real + d₂_real. 
Given: Apparent depth from one side (d₁_app) = 5 cm. Apparent depth from the other side (d₂_app) = 2 cm. Refractive index of glass μ = 1.5. 
From the formula, d_real = d_app * μ. 
For the first side: d₁_real = d₁_app * μ = 5 cm * 1.5 = 7.5 cm. 
For the second side: d₂_real = d₂_app * μ = 2 cm * 1.5 = 3.0 cm. 
Now, calculate the total thickness of the slab: T = d₁_real + d₂_real = 7.5 cm + 3.0 cm = 10.5 cm. This matches option (c).

Answer

2.5 cm

Answer

7.5 cm

Answer

10.5 cm

Answer

17.5 cm

Related Questionsin Physics

More from CUET UG

Browse CUET Questions by Subject

Practice More CUET UG Questions