Q29. A 25 µF capacitor, a 0.10 H inductor and a 25 Ω resistor is connected in series with an ac sour

Q: What is the correct answer for CUET UG Physics Q29?

The correct answer is c. The instantaneous electromotive force (emf) of an AC source is generally represented by the equation ε = ε₀ sin(ωt), where ε₀ is the peak emf, ω is the angular frequency, and t is time. We are given the emf equation as ε = 310 sin(314t). By comparing this with the general form, we can identify the angular frequency ω = 314 rad/s. The frequency (f) of the AC source is related to the angular frequen

Q: Q29. A 25 µF capacitor, a 0.10 H inductor and a 25 Ω resistor is connected in series with an ac source of emf ε = 310 sin 314 t. What is the frequency of AC source? (a) 314 Hz (b) 100 Hz (c) 50…

The correct answer is c. The instantaneous electromotive force (emf) of an AC source is generally represented by the equation ε = ε₀ sin(ωt), where ε₀ is the peak emf, ω is the angular frequency, and t is time. We are given the emf equation as ε = 310 sin(314t). By comparing this with the general form, we can identify the angular frequency ω = 314 rad/s. The frequency (f) of the AC source is related to the angular frequen

Q: What are the options for this CUET UG Physics question?

A. 314 Hz · B. 100 Hz · C. 50 Hz · D. 310 Hz

Question

Q29. A 25 µF capacitor, a 0.10 H inductor and a 25 Ω resistor is connected in series with an ac source of emf ε = 310 sin 314 t. What is the frequency of AC source?
(a) 314 Hz
(b) 100 Hz
(c) 50 Hz
(d) 310 Hz

FirstInTest · Accepted Answer

The instantaneous electromotive force (emf) of an AC source is generally represented by the equation ε = ε₀ sin(ωt), where ε₀ is the peak emf, ω is the angular frequency, and t is time. We are given the emf equation as ε = 310 sin(314t). By comparing this with the general form, we can identify the angular frequency ω = 314 rad/s. The frequency (f) of the AC source is related to the angular frequency by the formula ω = 2πf. Therefore, to find the frequency, we rearrange the formula to f = ω / (2π). Substituting the value of ω and using π ≈ 3.14, we get f = 314 rad/s / (2 * 3.14) = 314 / 6.28 = 50 Hz. The values of the capacitor, inductor, and resistor are extraneous information for determining the source frequency. Options (a), (b), and (d) are incorrect frequencies.

Answer

314 Hz

Answer

100 Hz

Answer

50 Hz

Answer

310 Hz

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