Q23. In the circuit shown below, the potential difference between A and B is:
[Circuit diagram showi

Q: What is the correct answer for CUET UG Physics Q23?

The correct answer is c. The circuit can be analyzed as three voltage sources (batteries) connected in parallel, each with an internal resistance (the 1Ω resistor in each branch). The potential difference between A and B would be the equivalent voltage (V_eq) of this parallel combination.The formula for the equivalent voltage of 'n' parallel voltage sources with internal resistances is given by:V_eq = (Σ (E_i / R_i)) / (Σ

Q: Q23. In the circuit shown below, the potential difference between A and B is: [Circuit diagram showing three parallel branches, each with a 1Ω resistor and a battery (1V, 2V, 3V). Points A and B are…

The correct answer is c. The circuit can be analyzed as three voltage sources (batteries) connected in parallel, each with an internal resistance (the 1Ω resistor in each branch). The potential difference between A and B would be the equivalent voltage (V_eq) of this parallel combination.The formula for the equivalent voltage of 'n' parallel voltage sources with internal resistances is given by:V_eq = (Σ (E_i / R_i)) / (Σ

Q: What are the options for this CUET UG Physics question?

A. 6 V · B. 3 V · C. 2 V · D. 1 V

Question

Q23. In the circuit shown below, the potential difference between A and B is:
[Circuit diagram showing three parallel branches, each with a 1Ω resistor and a battery (1V, 2V, 3V). Points A and B are across the equivalent combination.]
(a) 6 V
(b) 3 V
(c) 2 V
(d) 1 V

FirstInTest · Accepted Answer

The circuit can be analyzed as three voltage sources (batteries) connected in parallel, each with an internal resistance (the 1Ω resistor in each branch). The potential difference between A and B would be the equivalent voltage (V_eq) of this parallel combination.The formula for the equivalent voltage of 'n' parallel voltage sources with internal resistances is given by:V_eq = (Σ (E_i / R_i)) / (Σ (1 / R_i))Here, we have three branches:Branch 1: E₁ = 1V, R₁ = 1ΩBranch 2: E₂ = 2V, R₂ = 1ΩBranch 3: E₃ = 3V, R₃ = 1ΩPlugging these values into the formula:V_eq = [(1V/1Ω) + (2V/1Ω) + (3V/1Ω)] / [(1/1Ω) + (1/1Ω) + (1/1Ω)]V_eq = [1 A + 2 A + 3 A] / [1 S + 1 S + 1 S] (where S is Siemens, unit of conductance)V_eq = 6 A / 3 S = 2 V.Therefore, the potential difference between A and B is 2 V.

Answer

6 V

Answer

3 V

Answer

2 V

Answer

1 V

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