Q2. Match List - I with List - II.
LIST - I
(A) [M° L-2 T⁰ A¹]
(B) [M-1 L-2 T3 A2]
(C) [M L³ T-3 A-2

Q: What is the correct answer for CUET UG Physics Q2?

The correct answer is c. (A) Current density (J) is current per unit area (I/A). Dimensions: [A]/[L²] = [M⁰L⁻²T⁰A¹]. So (A)-(III).(B) Conductance (G) is the reciprocal of resistance (1/R). Resistance R = V/I. Voltage V = Work/Charge = [ML²T⁻²]/[AT] = [ML²T⁻³A⁻¹]. So, G = [A]/[ML²T⁻³A⁻¹] = [M⁻¹L⁻²T³A²]. So (B)-(I).(C) Specific resistance (ρ), also known as resistivity, is given by R = ρL/A, so ρ = RA/L. Dimensions: [ML²T⁻³

Q: Q2. Match List - I with List - II. LIST - I (A) [M° L-2 T⁰ A¹] (B) [M-1 L-2 T3 A2] (C) [M L³ T-3 A-2] (D) [M-1 L-3 T+3 A+2] LIST - II (I) Conductance (II) Electrical conductivity (III) Current…

The correct answer is c. (A) Current density (J) is current per unit area (I/A). Dimensions: [A]/[L²] = [M⁰L⁻²T⁰A¹]. So (A)-(III).(B) Conductance (G) is the reciprocal of resistance (1/R). Resistance R = V/I. Voltage V = Work/Charge = [ML²T⁻²]/[AT] = [ML²T⁻³A⁻¹]. So, G = [A]/[ML²T⁻³A⁻¹] = [M⁻¹L⁻²T³A²]. So (B)-(I).(C) Specific resistance (ρ), also known as resistivity, is given by R = ρL/A, so ρ = RA/L. Dimensions: [ML²T⁻³

Q: What are the options for this CUET UG Physics question?

A. (A)-(III), (B)-(II), (C)-(I), (D)-(IV) · B. (A)-(II), (B)-(I), (C)-(III), (D)-(IV) · C. (A)-(III), (B)-(I), (C)-(IV), (D)-(II) · D. (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Question

Q2. Match List - I with List - II.
LIST - I
(A) [M° L-2 T⁰ A¹]
(B) [M-1 L-2 T3 A2]
(C) [M L³ T-3 A-2]
(D) [M-1 L-3 T+3 A+2]
LIST - II
(I) Conductance
(II) Electrical conductivity
(III) Current density
(IV) Specific resistance
Choose the correct answer from the options given below:
(a) (A)-(III), (B)-(II), (C)-(I), (D)-(IV)
(b) (A)-(II), (B)-(I), (C)-(III), (D)-(IV)
(c) (A)-(III), (B)-(I), (C)-(IV), (D)-(II)
(d) (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

FirstInTest · Accepted Answer

(A) Current density (J) is current per unit area (I/A). Dimensions: [A]/[L²] = [M⁰L⁻²T⁰A¹]. So (A)-(III).(B) Conductance (G) is the reciprocal of resistance (1/R). Resistance R = V/I. Voltage V = Work/Charge = [ML²T⁻²]/[AT] = [ML²T⁻³A⁻¹]. So, G = [A]/[ML²T⁻³A⁻¹] = [M⁻¹L⁻²T³A²]. So (B)-(I).(C) Specific resistance (ρ), also known as resistivity, is given by R = ρL/A, so ρ = RA/L. Dimensions: [ML²T⁻³A⁻²] * [L²]/[L] = [ML³T⁻³A⁻²]. So (C)-(IV).(D) Electrical conductivity (σ) is the reciprocal of resistivity (1/ρ). Dimensions: 1/[ML³T⁻³A⁻²] = [M⁻¹L⁻³T⁴A²]. So (D)-(II).The correct match is (A)-(III), (B)-(I), (C)-(IV), (D)-(II).

Answer

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

Answer

(A)-(II), (B)-(I), (C)-(III), (D)-(IV)

Answer

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Answer

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

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