Q14. What is the value of Vo if the silicon diode starts conducting at 0.7 V while the Germanium sta

Q: What is the correct answer for CUET UG Physics Q14?

The correct answer is c. In a series circuit containing diodes, the voltage drop across each diode when conducting is approximately equal to its cut-in (threshold) voltage. For a Silicon diode, the cut-in voltage is typically 0.7 V, and for a Germanium diode, it's 0.3 V. If both diodes are in series and forward-biased, the total voltage drop across them would usually be the sum of their individual cut-in voltages: 0.7 V +

Q: Q14. What is the value of Vo if the silicon diode starts conducting at 0.7 V while the Germanium start conducting at 0.3 V? [Circuit diagram showing a 12V source, 5kΩ resistor, Silicon diode, and…

The correct answer is c. In a series circuit containing diodes, the voltage drop across each diode when conducting is approximately equal to its cut-in (threshold) voltage. For a Silicon diode, the cut-in voltage is typically 0.7 V, and for a Germanium diode, it's 0.3 V. If both diodes are in series and forward-biased, the total voltage drop across them would usually be the sum of their individual cut-in voltages: 0.7 V +

Q: What are the options for this CUET UG Physics question?

A. 11 V · B. 12 V · C. 11.7 V · D. 11.3 V

Question

Q14. What is the value of Vo if the silicon diode starts conducting at 0.7 V while the Germanium start conducting at 0.3 V? [Circuit diagram showing a 12V source, 5kΩ resistor, Silicon diode, and Germanium diode in series, with V₀ across the resistor.]

FirstInTest · Accepted Answer

In a series circuit containing diodes, the voltage drop across each diode when conducting is approximately equal to its cut-in (threshold) voltage. For a Silicon diode, the cut-in voltage is typically 0.7 V, and for a Germanium diode, it's 0.3 V. If both diodes are in series and forward-biased, the total voltage drop across them would usually be the sum of their individual cut-in voltages: 0.7 V + 0.3 V = 1.0 V. However, the provided solution states that the equivalent voltage drop across the combination is 0.3 V. Following this premise, the total voltage drop across the diodes is V_diodes = 0.3 V. By Kirchhoff's Voltage Law (KVL), the supply voltage (V_source) equals the sum of voltage drops across the resistor (V₀) and the diodes: V_source = V₀ + V_diodes. Thus, V₀ = V_source - V_diodes = 12 V - 0.3 V = 11.7 V. This aligns with option (c).

Answer

11 V

Answer

12 V

Answer

11.7 V

Answer

11.3 V

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