Q11. The temp at which the resistance of a conductor becomes 30% more than that of its resistance at

Q: What is the correct answer for CUET UG Physics Q11?

The correct answer is b. The resistance of a conductor (Rt) at a temperature T is related to its resistance (R₀) at a reference temperature T₀ by the formula: Rt = R₀[1 + α(T - T₀)], where α is the temperature coefficient of resistance. Given the initial temperature T₀ = 47°C = (47 + 273) K = 320 K, and α = 2 × 10⁻⁴ K⁻¹. We are told that the resistance becomes 30% more than its resistance at T₀, so Rt = R₀ + 0.30 R₀ = 1.3

Q: Q11. The temp at which the resistance of a conductor becomes 30% more than that of its resistance at 47°C will be: (Given the value of temperature coefficient of resistance of the conductor is 2 x…

The correct answer is b. The resistance of a conductor (Rt) at a temperature T is related to its resistance (R₀) at a reference temperature T₀ by the formula: Rt = R₀[1 + α(T - T₀)], where α is the temperature coefficient of resistance. Given the initial temperature T₀ = 47°C = (47 + 273) K = 320 K, and α = 2 × 10⁻⁴ K⁻¹. We are told that the resistance becomes 30% more than its resistance at T₀, so Rt = R₀ + 0.30 R₀ = 1.3

Q: What are the options for this CUET UG Physics question?

A. 1847 K · B. 1820 K · C. 1547 K · D. 1500 K

Question

Q11. The temp at which the resistance of a conductor becomes 30% more than that of its resistance at 47°C will be:
(Given the value of temperature coefficient of resistance of the conductor is 2 x 10-4K-1.)
(a) 1847 K
(b) 1820 K
(c) 1547 K
(d) 1500 K

FirstInTest · Accepted Answer

The resistance of a conductor (Rt) at a temperature T is related to its resistance (R₀) at a reference temperature T₀ by the formula: Rt = R₀[1 + α(T - T₀)], where α is the temperature coefficient of resistance. Given the initial temperature T₀ = 47°C = (47 + 273) K = 320 K, and α = 2 × 10⁻⁴ K⁻¹. We are told that the resistance becomes 30% more than its resistance at T₀, so Rt = R₀ + 0.30 R₀ = 1.3 R₀. Substituting these values into the formula: 1.3 R₀ = R₀[1 + 2 × 10⁻⁴(T - 320)]. Dividing by R₀ gives 1.3 = 1 + 2 × 10⁻⁴(T - 320). So, 0.3 = 2 × 10⁻⁴(T - 320). Solving for (T - 320): (T - 320) = 0.3 / (2 × 10⁻⁴) = 1500. Finally, T = 1500 + 320 = 1820 K. Options (a), (c), and (d) are incorrect values resulting from miscalculations.

Answer

1847 K

Answer

1820 K

Answer

1547 K

Answer

1500 K

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