The age distribution of 40 children is as follows: Age (in yr.) 5-6, 6-7, 7-8, 8-9, 9-10, 10-11. No.

Q: What is the correct answer for CUET UG Mathematics?

The correct answer is D. Given data: Age (in yr.): 5-6, 6-7, 7-8, 8-9, 9-10, 10-11 Frequency (No. of children): 4, 7, 9, 12, 6, 2 Total number of children (N) = $4+7+9+12+6+2 = 40$. Cumulative Frequencies: 5-6: 4 6-7: $4+7 = 11$ 7-8: $11+9 = 20$ 8-9: $20+12 = 32$ 9-10: $32+6 = 38$ 10-11: $38+2 = 40$ (A) The median of the age distribution is 7 yr. Median position = $N/2 = 40/2 = 20$. The 20th observation falls in the 7-8

Q: The age distribution of 40 children is as follows: Age (in yr.) 5-6, 6-7, 7-8, 8-9, 9-10, 10-11. No. of children 4, 7, 9, 12, 6, 2. Consider the following statements in respect of the above frequency…

The correct answer is D. Given data: Age (in yr.): 5-6, 6-7, 7-8, 8-9, 9-10, 10-11 Frequency (No. of children): 4, 7, 9, 12, 6, 2 Total number of children (N) = $4+7+9+12+6+2 = 40$. Cumulative Frequencies: 5-6: 4 6-7: $4+7 = 11$ 7-8: $11+9 = 20$ 8-9: $20+12 = 32$ 9-10: $32+6 = 38$ 10-11: $38+2 = 40$ (A) The median of the age distribution is 7 yr. Median position = $N/2 = 40/2 = 20$. The 20th observation falls in the 7-8

Q: What are the options for this CUET UG Mathematics question?

A. and (B) only · B. and (C) only · C. and (C) only · D. , (B) and (C) only

Question

The age distribution of 40 children is as follows: Age (in yr.) 5-6, 6-7, 7-8, 8-9, 9-10, 10-11. No. of children 4, 7, 9, 12, 6, 2. Consider the following statements in respect of the above frequency distribution. (A) The median of the age distribution is 7 yr. (B) 70% of the children are in the age group 6-9 yr. (C) The modal class of the children is 8-9 yr. Which of the above statements are true? Choose the correct answer from the options given below:

FirstInTest · Accepted Answer

Given data:
Age (in yr.): 5-6, 6-7, 7-8, 8-9, 9-10, 10-11
Frequency (No. of children): 4, 7, 9, 12, 6, 2
Total number of children (N) = $4+7+9+12+6+2 = 40$.

Cumulative Frequencies:
5-6: 4
6-7: $4+7 = 11$
7-8: $11+9 = 20$
8-9: $20+12 = 32$
9-10: $32+6 = 38$
10-11: $38+2 = 40$

(A) The median of the age distribution is 7 yr.
Median position = $N/2 = 40/2 = 20$.
The 20th observation falls in the 7-8 age group (cumulative frequency 20). The median class is 7-8. The median value is approximately 7 years. (True)

(B) 70% of the children are in the age group 6-9 yr.
Children in age group 6-9 yr = (6-7) + (7-8) + (8-9) = $7 + 9 + 12 = 28$.
Percentage = $(28/40) 	imes 100\% = (7/10) 	imes 100\% = 70\%$. (True)

(C) The modal class of the children is 8-9 yr.
The modal class is the class with the highest frequency. The highest frequency is 12, which corresponds to the age group 8-9 yr. (True)

All statements (A), (B), and (C) are true. This corresponds to option 4.

Answer

and (B) only

Answer

and (C) only

Answer

and (C) only

Answer

, (B) and (C) only

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