Q48. Match the oxidation state of phosphorous in the following compounds to their counter parts in L

Q: What is the correct answer for CUET UG Chemistry Q48?

The correct answer is a. To determine the oxidation state of phosphorus (P), assume H = +1 and O = -2:(A) H₃PO₂: 3(+1) + P + 2(-2) = 0 ⇒ 3 + P - 4 = 0 ⇒ P = +1. So (A)-(III).(B) H₄P₂O₆: 4(+1) + 2P + 6(-2) = 0 ⇒ 4 + 2P - 12 = 0 ⇒ 2P = 8 ⇒ P = +4. So (B)-(IV).(C) H₃PO₃: 3(+1) + P + 3(-2) = 0 ⇒ 3 + P - 6 = 0 ⇒ P = +3. So (C)-(I).(D) H₃PO₄: 3(+1) + P + 4(-2) = 0 ⇒ 3 + P - 8 = 0 ⇒ P = +5. So (D)-(II).Thus, the correct matching

Q: Q48. Match the oxidation state of phosphorous in the following compounds to their counter parts in List II. List-I (A) H3PO2 (B) H4P2O6 (C) H3PO3 (D) H3PO4 List-II (I) +3 (II) +5 (III) +1 (IV)…

The correct answer is a. To determine the oxidation state of phosphorus (P), assume H = +1 and O = -2:(A) H₃PO₂: 3(+1) + P + 2(-2) = 0 ⇒ 3 + P - 4 = 0 ⇒ P = +1. So (A)-(III).(B) H₄P₂O₆: 4(+1) + 2P + 6(-2) = 0 ⇒ 4 + 2P - 12 = 0 ⇒ 2P = 8 ⇒ P = +4. So (B)-(IV).(C) H₃PO₃: 3(+1) + P + 3(-2) = 0 ⇒ 3 + P - 6 = 0 ⇒ P = +3. So (C)-(I).(D) H₃PO₄: 3(+1) + P + 4(-2) = 0 ⇒ 3 + P - 8 = 0 ⇒ P = +5. So (D)-(II).Thus, the correct matching

Q: What are the options for this CUET UG Chemistry question?

A. (A)-(III), (B)-(IV), (C)-(I), (D)-(II) · B. (A)-(III), (B)-(I), (C)-(II), (D)-(IV) · C. (A)-(I), (B)-(III), (C)-(II), (D)-(IV) · D. (A)-(I), (B)-(IV), (C)-(II), (D)-(III)

Question

Q48. Match the oxidation state of phosphorous in the following compounds to their counter parts in List II.
List-I
(A) H3PO2
(B) H4P2O6
(C) H3PO3
(D) H3PO4
List-II
(I) +3
(II) +5
(III) +1
(IV) +4
Choose the correct answer from the options given below:
(a) (A)-(III), (B)-(IV), (C)-(I), (D)-(II)
(b) (A)-(III), (B)-(I), (C)-(II), (D)-(IV)
(c) (A)-(I), (B)-(III), (C)-(II), (D)-(IV)
(d) (A)-(I), (B)-(IV), (C)-(II), (D)-(III)

FirstInTest · Accepted Answer

To determine the oxidation state of phosphorus (P), assume H = +1 and O = -2:(A) H₃PO₂: 3(+1) + P + 2(-2) = 0 ⇒ 3 + P - 4 = 0 ⇒ P = +1. So (A)-(III).(B) H₄P₂O₆: 4(+1) + 2P + 6(-2) = 0 ⇒ 4 + 2P - 12 = 0 ⇒ 2P = 8 ⇒ P = +4. So (B)-(IV).(C) H₃PO₃: 3(+1) + P + 3(-2) = 0 ⇒ 3 + P - 6 = 0 ⇒ P = +3. So (C)-(I).(D) H₃PO₄: 3(+1) + P + 4(-2) = 0 ⇒ 3 + P - 8 = 0 ⇒ P = +5. So (D)-(II).Thus, the correct matching is (A)-(III), (B)-(IV), (C)-(I), (D)-(II).

Answer

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Answer

(A)-(III), (B)-(I), (C)-(II), (D)-(IV)

Answer

(A)-(I), (B)-(III), (C)-(II), (D)-(IV)

Answer

(A)-(I), (B)-(IV), (C)-(II), (D)-(III)

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