Q33. In inorganic salt analysis, for the indicatory test of Cl⁻, conc. H₂SO₄ is used. This is becaus

Q: What is the correct answer for CUET UG Chemistry Q33?

The correct answer is d. In the qualitative analysis of anions, concentrated sulfuric acid (H₂SO₄) is used to test for halides (like Cl⁻, Br⁻, I⁻) based on its non-volatile nature.- **Displacement of volatile acids:** Concentrated H₂SO₄ has a high boiling point (less volatile) compared to hydrogen halides (HCl, HBr, HI). When a salt containing a halide (e.g., NaCl) reacts with concentrated H₂SO₄, the more volatile hydro

Q: Q33. In inorganic salt analysis, for the indicatory test of Cl⁻, conc. H₂SO₄ is used. This is because:

The correct answer is d. In the qualitative analysis of anions, concentrated sulfuric acid (H₂SO₄) is used to test for halides (like Cl⁻, Br⁻, I⁻) based on its non-volatile nature.- **Displacement of volatile acids:** Concentrated H₂SO₄ has a high boiling point (less volatile) compared to hydrogen halides (HCl, HBr, HI). When a salt containing a halide (e.g., NaCl) reacts with concentrated H₂SO₄, the more volatile hydro

Q: What are the options for this CUET UG Chemistry question?

A. Conc. H₂SO₄ is a strong oxidising agent and Cl₂ is produced. · B. Conc. H₂SO₄ is a strong reducing agent and HCl is produced. · C. Conc. H₂SO₄ is a strong dehydrating agent and Cl₂ is produced. · D. Conc. H₂SO₄ has lower volatility than HCl.

Question

Q33. In inorganic salt analysis, for the indicatory test of Cl⁻, conc. H₂SO₄ is used. This is because:

FirstInTest · Accepted Answer

In the qualitative analysis of anions, concentrated sulfuric acid (H₂SO₄) is used to test for halides (like Cl⁻, Br⁻, I⁻) based on its non-volatile nature.-   **Displacement of volatile acids:** Concentrated H₂SO₄ has a high boiling point (less volatile) compared to hydrogen halides (HCl, HBr, HI). When a salt containing a halide (e.g., NaCl) reacts with concentrated H₂SO₄, the more volatile hydrogen halide gas is displaced:    NaCl(s) + H₂SO₄(conc.) → NaHSO₄(s) + HCl(g)    The HCl gas produced can then be identified (e.g., by white fumes with ammonia).Let's evaluate the given options:(a) Conc. H₂SO₄ is a strong oxidising agent and Cl₂ is produced: While concentrated H₂SO₄ is an oxidising agent, and Cl₂ can be produced from more reactive halides like Br⁻ or I⁻ with conc. H₂SO₄ (especially hot), for Cl⁻, the primary reaction at room temperature is the displacement of HCl. The production of Cl₂ (if any) would be a secondary, undesired reaction in the initial identification of Cl⁻.(b) Conc. H₂SO₄ is a strong reducing agent and HCl is produced: This is incorrect; H₂SO₄ is an oxidizing agent.(c) Conc. H₂SO₄ is a strong dehydrating agent and Cl₂ is produced: While H₂SO₄ is a strong dehydrating agent, this is not the primary reason for its use in displacing HCl, and Cl₂ is not primarily produced from Cl⁻.(d) Conc. H₂SO₄ has lower volatility than HCl: This is the correct reason. Its high boiling point (337°C) allows it to displace more volatile acids like HCl (b.p. -85°C) from their salts.

Answer

Conc. H₂SO₄ is a strong oxidising agent and Cl₂ is produced.

Answer

Conc. H₂SO₄ is a strong reducing agent and HCl is produced.

Answer

Conc. H₂SO₄ is a strong dehydrating agent and Cl₂ is produced.

Answer

Conc. H₂SO₄ has lower volatility than HCl.

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