Q21. Match List - I with List - II.
List - I (Complex ion)
(A) [CoF6]3-
(B) [Co(CN)4]2-
(C) [FeCl4]-

Q: What is the correct answer for CUET UG Chemistry Q21?

The correct answer is C. A. [CoF6]3-: Co is in +3 oxidation state (Co3+), which is d6. F- is a weak field ligand, so it forms a high spin outer orbital complex with sp3d2 hybridization. So (A) -> (II).B. [Co(CN)4]2-: Co is in +2 oxidation state (Co2+), which is d7. CN- is a strong field ligand. It forms a low spin square planar complex with dsp2 hybridization. So (B) -> (IV).C. [FeCl4]-: Fe is in +3 oxidation state (Fe3+)

Q: Q21. Match List - I with List - II. List - I (Complex ion) (A) [CoF6]3- (B) [Co(CN)4]2- (C) [FeCl4]- (D) [Co(C2O4)3]3- List - II (Hybridisation) (I) d2sp3 (II) sp3d2 (III) sp3 (IV) dsp2 Choose the…

The correct answer is C. A. [CoF6]3-: Co is in +3 oxidation state (Co3+), which is d6. F- is a weak field ligand, so it forms a high spin outer orbital complex with sp3d2 hybridization. So (A) -> (II).B. [Co(CN)4]2-: Co is in +2 oxidation state (Co2+), which is d7. CN- is a strong field ligand. It forms a low spin square planar complex with dsp2 hybridization. So (B) -> (IV).C. [FeCl4]-: Fe is in +3 oxidation state (Fe3+)

Q: What are the options for this CUET UG Chemistry question?

A. (a) (A)-(II), (B)-(III), (C)-(IV), (D)-(I) · B. (b) (A)-(I), (B)-(IV), (C)-(III), (D)-(II) · C. (c) (A)-(II), (B)-(IV), (C)-(III), (D)-(I) · D. (d) (A)-(I), (B)-(III), (C)-(IV), (D)-(II)

Question

Q21. Match List - I with List - II.
List - I (Complex ion)
(A) [CoF6]3-
(B) [Co(CN)4]2-
(C) [FeCl4]-
(D) [Co(C2O4)3]3-
List - II (Hybridisation)
(I) d2sp3
(II) sp3d2
(III) sp3
(IV) dsp2
Choose the correct answer from the options given below:
(a) (A)-(II), (B)-(III), (C)-(IV), (D)-(I)
(b) (A)-(I), (B)-(IV), (C)-(III), (D)-(II)
(c) (A)-(II), (B)-(IV), (C)-(III), (D)-(I)
(d) (A)-(I), (B)-(III), (C)-(IV), (D)-(II)

FirstInTest · Accepted Answer

A. [CoF6]3-: Co is in +3 oxidation state (Co3+), which is d6. F- is a weak field ligand, so it forms a high spin outer orbital complex with sp3d2 hybridization. So (A) -> (II).B. [Co(CN)4]2-: Co is in +2 oxidation state (Co2+), which is d7. CN- is a strong field ligand. It forms a low spin square planar complex with dsp2 hybridization. So (B) -> (IV).C. [FeCl4]-: Fe is in +3 oxidation state (Fe3+), which is d5. Cl- is a weak field ligand. It forms a high spin tetrahedral complex with sp3 hybridization. So (C) -> (III).D. [Co(C2O4)3]3-: Co is in +3 oxidation state (Co3+), which is d6. C2O42- (oxalate) is a strong field ligand. It forms a low spin inner orbital complex with d2sp3 hybridization. So (D) -> (I).Therefore, the correct match is (A)-(II), (B)-(IV), (C)-(III), (D)-(I).

Answer

(a) (A)-(II), (B)-(III), (C)-(IV), (D)-(I)

Answer

(b) (A)-(I), (B)-(IV), (C)-(III), (D)-(II)

Answer

(c) (A)-(II), (B)-(IV), (C)-(III), (D)-(I)

Answer

(d) (A)-(I), (B)-(III), (C)-(IV), (D)-(II)

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