Q23. Match List I with List II
List - I
A. Cr3+
B. Mn4+
C. Cu+
D. Ti4+
List - II
I. d³ configuration
II. d10 configuration
III. Paramagnetic
IV. Diamagnetic
Choose the correct answer from the options

Question

Q23. Match List I with List II
List - I
A. Cr3+
B. Mn4+
C. Cu+
D. Ti4+
List - II
I. d³ configuration
II. d10 configuration
III. Paramagnetic
IV. Diamagnetic
Choose the correct answer from the options given below:
(a) A-II, B-III, C-IV, D-I
(b) A-IV, B-III, C-I, D-II
(c) A-I, B-III, C-II, D-IV
(d) A-I, B-II, C-III, D-IV

FirstInTest · Accepted Answer

Correct answer: c. A. For the electronic configuration of the Cr3+ ion, we will remove three electrons from the Cr (one from the 4s1 and two from the 3d5), leaving us with 1s22s22p63s23p63d3 or [Ar]3d3. So Cr3+ is d3. (A-I)B. The manganese (IV) oxide is the second most strongly attracted compound, and is paramagnetic. (Mn4+ = [Ar]3d3, 3 unpaired electrons). So Mn4+ is d3 configuration and paramagnetic. (B-III)C. Cu⁺¹ compound are diamagnetic in nature. the outer configuration is 3d10 and therefore it has all paired electrons in Cu+¹ oxidation state. So Cu+ is d10. (C-II, IV)D. Electronic configuration of. 22Ti4+ is [Ar]183d04s0. So all electrons are paired and thus its all complexes are diamagnetic. (Ti4+ is d0, diamagnetic). (D-IV)Matches are: A-I, B-III, C-II, D-IV. This matches option (c).

Related Questionsin Chemistry (Coordination Compounds)

Practice More CUET UG Questions